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svetoff [14.1K]
3 years ago
14

What is Saponification!?

Chemistry
1 answer:
Tom [10]3 years ago
8 0

Answer:

<h3>Saponification is a process that involves conversion of fat, oil or lipid into soap and alcohol by the action of heat in the presence of aqueous alkali. Soaps are salts of fatty acids and fatty acids are monocarboxylic acids that have long carbon chains e.g. sodium palmitate.</h3>
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Has highest melting point of two bonds
Liono4ka [1.6K]

Answer:

Ionic compounds

Explanation:

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3 years ago
Do states need to be written in a chemical equation
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Yes. because equation balances the number of particles.
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A section of the periodic table is shown below: A portion of two rows of the periodic table is shown. The first row reads two he
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 The statement  which is true  is

Fluorine  is more reactive  than nitrogen because fluorine  needs  only  one electron to fill  its  outermost  shell.


     <u><em>Explanation</em></u>

Fluorine  has  electron configuration  of 1S²2S²2P⁵  while nitrogen  has 1S²2S²2P³  electron configuration.

The 2P sub shell  for nitrogen   is  half filled  therefore it is sable  than fluorine.

since  p orbital  can hold a maximum  of  6  electrons ,Fluorine  requires  1 electron  to  completely fill  it's 2P  sub shell  which make it    more  reactive than nitrogen.



7 0
3 years ago
I2(g) + Cl2(g)2ICl(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 1.62 mol
galina1969 [7]

Answer:

The change in entropy of the surrounding is -146.11 J/K.

Explanation:

Enthalpy of formation of iodine gas = \Delta H_f_{(I_2)}=62.438 kJ/mol

Enthalpy of formation of chlorine gas = \Delta H_f_{(Cl_2)}=0 kJ/mol

Enthalpy of formation of ICl gas = \Delta H_f_{(ICl)}=17.78 kJ/mol

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

I_2(g)+Cl_2(g)\rightarrow 2ICl(g),\Delta H_{rxn}=?

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(2\times \Delta H_f_{(ICl)})]-[(1\times \Delta H_f_{(I_2)})+(1\times \Delta H_f_{(Cl_2)})]

=[2\times 17.78 kJ/mol]-[1\times 0 kJ/mol+1\times 62.436 kJ/mol]=-26.878 kJ/mol

Enthaply change when 1.62 moles of iodine gas recast:

\Delta H= \Delta H_{rxn}\times 1.62 mol=(-26.878 kJ/mol)\times 1.62 mol=-43.542 kJ

Entropy of the surrounding = \Delta S^o_{surr}=\frac{\Delta H}{T}

=\frac{-43.542 kJ}{298 K}=\frac{-43,542 J}{298 K}=-146.11 J/K

1 kJ = 1000 J

The change in entropy of the surrounding is -146.11 J/K.

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3 years ago
Chemical calculation. don't have to rush, take your time.
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what is the formula of rectangle

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