195 ÷ 4 = 48.75
Is this what you wanted?
Okay, so this is just a basic multiplication problem. first, we need to divide to figure out how much the trout population grows after 1 year. If it doubles in 4 years, then it will rise by a quarter each single year. So to put that in terms of fractions, then for every year, the equation would be 250x1/4. So then we do the equation, coming up with 62.5. This means that the population rises roughly 63 fish a year. So after 1 year, you will have roughly 313 fish. (312.5 to be exact). Then to get that by ten years, we can just multiply the number that we got for one year by ten. 62.5x10=625. So then we add the 250 original trout, and 250+625=875. So after 10 years, there will be 875 trout.
Answer:
If the rest of the question is:
Each game is a win or a loss.
He wins three fifths of his first 40 games.
He then wins his next 12 games.
For all 52 games, work out the ratio wins : losses
Give your answer in its simplest form.
then the answer is below ↓
Step-by-step explanation:
9:4
of his first 40 games: 3/5 *40=3*8=24 wins
=> of his first 40 games: 24 wins and 40-24=16 losses
next 12 games: 12 wins
so, for all 52 games: 24+12=36 wins and 16 losses
36 wins and 16 losses
wins: losses=> 36:16=> 9:4
