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maria [59]
3 years ago
10

You're trying to enlarge an image that is 4 centimeters tall and 10 centimeters wide onto a billboard that is 3 meters tall and

8 meters wide. What is the height scale?
Mathematics
1 answer:
torisob [31]3 years ago
7 0

The height scale is 75

<em><u>Solution:</u></em>

Given that you are trying to enlarge an image that is 4 centimeters tall and 10 centimeters wide onto a billboard that is 3 meters tall and 8 meters wide

We have to find the height scale

From given information,

Height of original image = 4 cm

Height of enlarged image = 3 meters

Both the units are different.

Let us convert 4 cm to meter

<em><u>Use the following conversion factor</u></em>

1 cm = 0.01 meter

4 cm = 4 x 0.01 meter = 0.04 meter

<em><u>What is the height scale?</u></em>

<em><u>Height scale is found by following:</u></em>

height\ scale = \frac{height\ of\ enlarged\ image}{height\ of\ original\ image}

height\ scale = \frac{3\ meter}{0.04\ meter}\\\\height scale = \frac{3}{0.04} = 75

Thus height scale is 75

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Each tile is 3/2 feet by 3/2 feet. There are 10 tiles on the bathroom floor.
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9514 1404 393

Answer:

  22.5 square feet

Step-by-step explanation:

The area covered by one tile is the product of its dimensions:

  A = lw

  A = (3/2 ft)(3/2 ft) = 9/4 ft²

The area covered by 10 tiles is 10 times the area covered by one tile. The area covered is ...

  covered by tiles = 10 × 9/4 ft² = 90/4 ft²

  covered by tiles = 22.5 ft²

22 1/2 square feet is the area covered by tiles.

4 0
3 years ago
The green river freeway has a minimum and maximum speed limit, tony drove for 2 hours at the minimum speed limit and 3.5 hours a
Vinil7 [7]
From the beginning we know we are dealing with two different rates. Distance is equal to (Speed X Time). We have two different speeds though. We will call the min speed = x and the max speed = y.  With those two ideas in place we can make two equations for both Tony and Rae.
Tony:
2x+3.5y=355
Rae:
2x+3y=320
Now you can solve the equations by subtracting Rae's equation from Tony's

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6 0
3 years ago
Suppose that the regression for predicting weight (in pounds) from Height (in Select one answer inches) is given by Weight =-115
Nutka1998 [239]

Answer:

Option D)  I and II only                                    

Step-by-step explanation:

We are given the following in the question:

Regression equation:

w = -115 + 3.6h

where w is the weight in pounds and h is the height in inches.

Since the weight depends on height, height becomes the independent variable and weight becomes the dependent variable.

I. A person who is 61 inches tall will weigh 104.6 pounds

When h = 61,

w = -115 + 3.6(61) = 104.6

Thus, the given statement is true.

II. For every additional inch of height, the predicted weight will increase, on average, by 3.6 pounds.

If the height increases by 1 unit, then,

w(h+1) - w(h) = -115 + 3.6(h+1) - (-115 + 3.6(h))\\w(h+1) - w(h)  = 3.6(h+1-h)\\w(h+1) - w(h)  = 3.6

Thus, the given statement is correct.

III. The correlation between weight and height is negative.

No, the given statement is not correct as with increase in height the weight increases and with decrease in height the weight decreases.

Thus, the correct answer is

Option D)  I and II only

8 0
3 years ago
Can someone please help me I don’t know if you got to have to add 4 numbers or 2 numbers
Ghella [55]

Answer:

12 feet.

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You have to add 4 numbers.

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3 0
3 years ago
If 28% of students in College are near-sighted, the probability that in a randomly chosen group of 20 College students, exactly
cluponka [151]

Answer: (D) 16%

Step-by-step explanation:

Binomial probability formula :-

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Given : The proportion of students in College are near-sighted : p= 0.28

Sample size : n= 20

Then, the the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is given by :_

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Hence, the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is closest to 16%.

7 0
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