We can solve the problem by using Snell's law, which states
where
is the refractive index of the first medium
is the angle of incidence
is the refractive index of the second medium
is the angle of refraction
In our problem,
(refractive index of air),
and
(refractive index of carbon disulfide), therefore we can re-arrange the previous equation to calculate the angle of refraction:
From which we find
Answer:
They are formed on or near the Earth’s surface from the compression of ocean sediments or other processes.
Explanation:
The period of the orbit would increase as well
Explanation:
We can answer this question by applying Kepler's third law, which states that:
"The square of the orbital period of a planet around the Sun is proportional to the cube of the semi-major axis of its orbit"
Mathematically,
Where
T is the orbital period
a is the semi-major axis of the orbit
In this problem, the question asks what happens if the distance of the Earth from the Sun increases. Increasing this distance means increasing the semi-major axis of the orbit, 
: but as we saw from the previous equation, the orbital period of the Earth is proportional to , therefore as increases, T increases as well.
Therefore, the period of the orbit would increase.
Learn more about Kepler's third law:
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One of the many random useless factoids that I carry around
in my head is the factoid that 60 miles per hour is equivalent
to exactly 88 feet per second.
So in three seconds at that speed, you would cover exactly
(3 x 88) = 264 feet.
Answer:
Explanation:
Potential energy on the surface of the earth
= - GMm/ R
Potential at height h
= - GMm/ (R+h)
Potential difference
= GMm/ R - GMm/ (R+h)
= GMm ( 1/R - 1/ R+h )
= GMmh / R (R +h)
This will be the energy needed to launch an object from the surface of Earth to a height h above the surface.
Extra energy is needed to get the same object into orbit at height h
= Kinetic energy of the orbiting object at height h
= 1/2 x potential energy at height h
= 1/2 x GMm / ( R + h)
