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Minchanka [31]
3 years ago
15

What two sysrems of a rabbit's body must be working together to run away?

Physics
1 answer:
Delvig [45]3 years ago
8 0
Muscular, and Circulatory Fam.......................................
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What displacement in cm would occur with a 75 N/m spring if you placed a 300 N weight on the spring?
ollegr [7]

Surface tension=75N/m

Weight=300N

\\ \bull\tt\longmapsto Surface\:Tension=\dfrac{Weight}{Displacement}

\\ \bull\tt\longmapsto Displacement=\dfrac{Weight}{Surface\:Tension}

\\ \bull\tt\longmapsto Displacement=\dfrac{300}{75}

\\ \bull\tt\longmapsto Displacement=4m

\\ \bull\tt\longmapsto Displacement=400cm

6 0
3 years ago
Imagine a simple pendulum swinging in an elevator. If the cable holding the elevator up was to snap, allowing the elevator to go
Lady_Fox [76]

One of the components that affect the period is gravity (the other is length). This gravity is basically the value of the effective acceleration that acts on the body due to gravity. When the elevator is over free fall, the effective gravity becomes zero. Mathematically this can be visualized as,

T = 2\pi \sqrt{\frac{l}{\dot{g_{eff}}}}

Since this value is zero, the period would tend to be infinite,

T \rightarrow \infty

Therefore the frequency that is inversely proportional to the period would be defined as

f = \frac{1}{T}

f = \frac{1}{\infty}

f \approx 0

In this way there is no frequency on the body which will not generate any oscillation on the body

5 0
3 years ago
What would the final temperature be if 8.94 X 10 3 joules of heat were added to 454 grams of copper at 23.0 o C?
ozzi

Answer: 74.1^0C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed=8.94\times 10^3 Joules

m= mass of copper = 454 g

c = specific heat capacity = 0.385J/g^0C

Initial temperature of the copper = T_i = 23.0°C

Final temperature of the water = T_f  = ?

Change in temperature ,\Delta T=T_f-T_i

Putting in the values, we get:

8.94\times 10^3=454\times 0.385\times (T_f-23.0)^0C

T_f=74.1^0C

The final temperature of copper will be 74.1^0C

8 0
3 years ago
Consider a snooker ball, with a mass of 0.07kg, rolling along a table at a speed of 4.1m/s. It hits a side cushion of the snooke
zavuch27 [327]

Answer: - 3.4 \times 10^{-3} N

Explanation:

From Newton's law of motion, Force is equal to rate of change of momentum.

The initial velocity of the ball, u = 4.1 m/s

mass of the ball, m = 0.07 kg

During contact, velocity = 0

Time of contact, t = 72 ms = 72 × 10⁻³ s

F = \frac{m(v-u)}{t} = \frac{0.07 kg \times (0-4.1 m/s)}{72 \times 10^{-3}s} = - 3.4 \times10^{-3} N

Thus, net force applied to the ball during this collision is - 3.4 \times 10^{-3} N

4 0
3 years ago
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VARVARA [1.3K]
C good thing is that I have a good time at my
6 0
3 years ago
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