Answer:
The cannon has an initial speed of 13.25 m/s.
Explanation:
The launched cannonball is an example of a projectile. Thus, its launch speed can be determined by the application of the formula;
R = u
Where: R is the range of the projectile, u is its initial speed, H is the height of the cliff and g is the gravitaty.
R = 26.3 m, H = 19.3 m, g = 9.8 m/
.
So that:
26.3 = u
=
x 
691.69 =
x 
= 
= 
= 175.6104
⇒ u = 
= 13.2518
u = 13.25 m/s
The initial speed of the cannon is 13.25 m/s.
The x-component of a vector are < 106.6, 43.07 >
Depending on the angle we are provided, the x-component of a vector can either be cos or sin. Cos always corresponds to the right triangle's side that contacts the specified angle.
If a vector v with magnitude ||v|| makes an angle θ with the positive x-axis then,
v = ||v|| cos θi + ||v|| sin θj
= < ||v|| cos θ , ||v|| sin θ >
Magnitude p = 115 km
Angle = 22°
p = ||p|| < cos θ, sin θ >
p = 115 < cos 22°, sin 22° >
p = 115 < 0.927, 0.3746 >
p = < 106.6, 43.07 >
Therefore, the x-component of a vector are < 106.6, 43.07 >
Learn more about vectors here:
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Answer:
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Answer:
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Explanation:
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Answer:
= 53.4 m/s
Explanation:
Velocity of a sound is given by the formula;
Velocity = Frequency × 2 (Length)
Frequency = 30 Hz
Length = 89 cm, equivalent to 0.89 M
Therefore;
Velocity = 30 × 2 ×0.89
= 53.4 m/s
Thus; the velocity or the speed of sound is 53.4 m/s