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4 years ago

14

A block oscillating on a spring has a maximum speed of 20 cm/s. part a what will the block's maximum speed be if its total energ

y is doubled?

1 answer:

yKpoI14uk [10]4 years ago

6 0

It will be 4 times of original thus maximum speed would be 80cm/s

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How long would it take for someone to bike to school if the school is 10 km away and the

damaskus [11]

Answer:

It would take the cyclist 2 hours to cycle to school.

Explanation:

5km/hr for 2 hours would be 10km.

8 0

3 years ago

The magnitude of the force involved in a certain collision (measured in newtons) is equal to the change in momentum (measured in

Vinvika [58]

Answer:

The time-interval of the collision is $t=\frac{{\Delta}p}{F}$

Explanation:

As given the force is equal to the rate of change of momentum. Mathemticaly this is:

$F=\frac{dp}{dt}.$

We can rearrange this equation to solve for ${\delta}t$ which gives

$t=\frac{{\Delta}p}{F}$

which is our answer.

In words this means the time interval is equal to the momentum change in that interval divided by the force applied that caused this momentum change.

4 0

3 years ago

A 77 kg student traveling in a car with a constant velocity has a kinetic energy of 1.7 104 J. What is the speedometer reading o

AVprozaik [17]

ANSWER

75.65 km/h

EXPLANATION

Given:

• The student's mass, m = 77 kg

,

• The kinetic energy of the student in the car, KE = 1.7 x 10⁴ J

Find:

• The speed read in the speedometer of the car, which is the speed of the student, v (in km/h)

The kinetic energy of an object with mass m, traveling at a speed v, is,

$KE=\frac{1}{2}mv^2$

Solving for v,

$v=\sqrt{\frac{2KE}{m}}$

Replace the known values and solve,

$v=\sqrt{\frac{2\cdot1.7\cdot10^4J}{77kg}}\approx21.013m/s$

Note that because the kinetic energy is given in Joules - which is equivalent to kg*m²/s², the speed we found is in m/s. Now, knowing that there are 3600 seconds in 1 hour and that 1 km is equivalent to 1000 m, we can convert this to km/s,

$v=21.013\frac{m}{s}\cdot\frac{3600s}{1h}\cdot\frac{1km}{1000m}\approx75.65km/h$

Hence, the speedometer reading of the car is 75.65 km/h, rounded to the nearest hundredth.

7 0

2 years ago

g as measured from the earth, a spacecraft is moving at speed .80c toward a second spacecraft moving at speed .60c back toward t

cupoosta [38]

Answer:

the speed of the first spacecraft as viewed from the second spacecraft is 0.95c

Explanation:

Given that;

speed of the first spacecraft from earth v $_a$ = 0.80c

speed of the second spacecraft from earth v $_b$ = -0.60 c

Using the formula for relative motion in relativistic mechanics

u' = ( v $_a$ - v $_b$ ) / ( 1 - (v $_b$ v $_a$ / c²) )

we substitute

u' = ( 0.80c - ( -0.60c) ) / ( 1 - ( ( 0.80c × -0.60c) / c² ) )

u' = ( 0.80c + 0.60c ) / ( 1 - ( -0.48c² / c² ) )

u' = 1.4c / ( 1 - ( -0.48 ) )

u' = 1.4c / ( 1 + 0.48 )

u' = 1.4c / 1.48

u' = 0.9459c ≈ 0.95c { two decimal places }

Therefore, the speed of the first spacecraft as viewed from the second spacecraft is 0.95c

7 0

3 years ago

A forward-biased silicon diode is connected to a 6.0-V battery. Also in the circuit are three 220 Ω resistors connected in serie

o-na [289]

Answer:

Current in the circuit will be 0.024 A

Explanation:

We have given battery voltage v = 6 volt

Resistance R = 220 ohm

Diode potential $v_d$ = 0.7 volt

So voltage across the resistance = 6 - 0.7 = 5.3 volt

Current is given by $current=\frac{voltage}{reistance}=\frac{5.3}{220}=0.024A$

So current in the circuit will be 0.024 A

3 0

3 years ago