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marshall27 [118]
4 years ago
10

A blow-dryer and a vacuum cleaner each operate with a voltage of 120 V. The current rating of the blow-dryer is 10 A, and that o

f the vacuum cleaner is 4.0 A.
(a) Determine the power consumed by the blow-dryer.
______ W
(b) Determine the power consumed by the vacuum cleaner.______W(c) Determine the ratio of the energy used by the blow-dryer in 11 minutes to the energy used by the vacuum cleaner in one-half hour.Ebd / Evc = _____
Physics
1 answer:
Katyanochek1 [597]4 years ago
5 0

Answer:

Part a)

P = 1200 Watt

Part b)

P = 480 W

Part c)

\frac{E_{bd}}{E_{vc}} = 5 : 2

Explanation:

Part a)

Power consumed by blow dryer is given as

P = iV

here supply voltage is given as

V = 120 volts

current rating of blow dryer is given as

i = 10 A

P = (120 V)(10 A)

P = 1200 W

Part b)

Power consumed by vacuum cleaner is given as

P = iV

here supply voltage is given as

V = 120 volts

current rating of vacuum cleaner is given as

i = 4 A

P = (120 V)(4 A)

P = 480 W

Part c)

Energy consumed in a given interval of time is given as

Energy = power \times time

now we have to find the ratio of energy consumed in time interval of 11 minutes

so we have

\frac{E_{bd}}{E_{vc}} = \frac{P_{bd} t}{P_{vc} t}

now we have

\frac{E_{bd}}{E_{vc}} = \frac{1200 W\times 11 min}{480 W \times 11 min}

\frac{E_{bd}}{E_{vc}} = 5 : 2

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Answer:

4. Electrons move from higher energy states to lower energy states.

Explanation:

When electrons fall from a higher (excited) energy state to a lower energy state, it loses/gives out energy.

This energy is given out by the emission of photons (quanta of light) by the electron.

7 0
3 years ago
An open-topped freight car with mass 24,000 kg is coasting without friction along a level track. It is raining very hard, and th
skelet666 [1.2K]

Answer:

(a) v = 3..6 m/s

(b) The rain falling downward has been able to affect the horizontal motion of the car by reducing it's velocity from 4 m/s to 3.6 m/s.

Explanation:

from the question we have the following:

mass of the car (Mc) = 24,000 kg

initial velocity of the car (u) = 4 m/s

mass of water (Mw) = 3000 kg

final velocity of the car (v) = ?

(a) we can calculate the final momentum of the car by applying the conservation of momentum where

initial momentum = final momentum

Mc x U = (Mc + Mw) x V

24000 x 4 = (24000 + 3000) x v

96,000 = 27000v

v =3.6 m/s

(b) The rain falling downward has been able to affect the horizontal motion of the car by reducing it's velocity from 4 m/s to 3.6 m/s.

7 0
3 years ago
9. A mouse has a mass of 0. 4kg. What is its weight? (acceleration due to gravity on Earth is 9.8m/s2 = g)
Alik [6]

Answer:

Weight = 3.92 N

Explanation:

Given:

Mass m = 0.4 kg

Acceleration due to gravity g = 9.8 m/s²

Find:

Weight

Computation:

Weight = Mass x Acceleration due to gravity

Weight = 0.4 x 9.8

Weight = 3.92 N

8 0
3 years ago
How much voltage is in the primary coil if there are 3200 windings in the
Lesechka [4]

Answer:

Voltage in primary coil is 3.91 V

Explanation:

For transformer we know that the working principle is given as

\frac{V_1}{V_2} = \frac{N_1}{N_2}

here we know that

V_1 [tex] = voltage in primary coil[tex]V_2 = 25 V

N_1 = 500

N_2 = 3200

Now we have

\frac{V_1}{25} = \frac{500}{3200}

V_1 = 3.91 V

8 0
3 years ago
A 900 kg car speeds up from 30 M/S to 80 m/s how much momentum did the car gain?​
AlexFokin [52]

The change in momentum of the car is 45,000 kg m/s

Explanation:

The change in momentum of an object is given by:

\Delta p = m(v-u)

where

m is the mass of the object

u is its initial velocity

v is its final velocity

For the car in this problem, we have

m = 900 kg

u = 30 m/s

v = 80 m/s

Therefore, the change in momentum is:

\Delta p = (900)(80-30)=45,000 kg m/s

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

#LearnwithBrainly

3 0
3 years ago
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