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marshall27 [118]
3 years ago
10

A blow-dryer and a vacuum cleaner each operate with a voltage of 120 V. The current rating of the blow-dryer is 10 A, and that o

f the vacuum cleaner is 4.0 A.
(a) Determine the power consumed by the blow-dryer.
______ W
(b) Determine the power consumed by the vacuum cleaner.______W(c) Determine the ratio of the energy used by the blow-dryer in 11 minutes to the energy used by the vacuum cleaner in one-half hour.Ebd / Evc = _____
Physics
1 answer:
Katyanochek1 [597]3 years ago
5 0

Answer:

Part a)

P = 1200 Watt

Part b)

P = 480 W

Part c)

\frac{E_{bd}}{E_{vc}} = 5 : 2

Explanation:

Part a)

Power consumed by blow dryer is given as

P = iV

here supply voltage is given as

V = 120 volts

current rating of blow dryer is given as

i = 10 A

P = (120 V)(10 A)

P = 1200 W

Part b)

Power consumed by vacuum cleaner is given as

P = iV

here supply voltage is given as

V = 120 volts

current rating of vacuum cleaner is given as

i = 4 A

P = (120 V)(4 A)

P = 480 W

Part c)

Energy consumed in a given interval of time is given as

Energy = power \times time

now we have to find the ratio of energy consumed in time interval of 11 minutes

so we have

\frac{E_{bd}}{E_{vc}} = \frac{P_{bd} t}{P_{vc} t}

now we have

\frac{E_{bd}}{E_{vc}} = \frac{1200 W\times 11 min}{480 W \times 11 min}

\frac{E_{bd}}{E_{vc}} = 5 : 2

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