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Jet001 [13]
3 years ago
11

Two satellites are in circular orbits around Earth. Satellite A has speed vA. Satellite B has an orbital radius nine times that

of satellite A. What is the speed of satellite B
Physics
1 answer:
Pani-rosa [81]3 years ago
8 0

Answer:

option B

Explanation:

given,

Satellite B has an orbital radius nine times that of satellite A.

R' = 9 R

now, orbital velocity of the satellite A

........(1)

now, orbital velocity of satellite B

from equation 1

hence, the correct answer is option B

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A piece of copper is heated to 90°C and then lowered into a beaker of water at 20°C.
sergeinik [125]

Answer:

20kg

Explanation:

heat lost by copper=heat gained by watter

5 0
4 years ago
Which human body system provides nutrients for the body by breaking<br> down food? *
dimaraw [331]

Answer:

The digestive system provides nutrients to the body by breaking down food.

6 0
4 years ago
Two 120 Ω resistors are connected in parallel across a supply voltage of 10 VDC. What's the current in this circuit?
german

As we know that here two 120 ohm resistors are connected in parallel with the battery of voltage 10 V DC

now here we will use Ohm's law

V = i R

so here we can use above equation to find the current in each resistor

10 = i \times 120

i = \frac{10}{120}

i = 0.0833 A

so here this will be the current flow through each resistor

now the total current through both resistors will be given as

i_{total} = 0.0833 + 0.0833 = 0.167 A


8 0
3 years ago
Read 2 more answers
What is the acceleration of a 7 kg mass pushed by a 3.5 N force?
defon

Answer:

0.5m/s²

Explanation:

F =m x a

3.5 = 7 x a

a = 3.5 /7

a = 0.5m/s ²

4 0
3 years ago
An object with a mass of 0. 25 kg is undergoing simple harmonic motion at the end of a vertical spring with a spring constant, k
skelet666 [1.2K]

Answer:

1) The amplitude of the motion is approximately 0.274 meters.

2) The total energy of the object at any point of its motion is 16.892 joules.

Explanation:

1) An object under simple harmonic motion is conservative, since there is no dissipative forces acting during motion (i.e. friction, air viscosity). The amplitude of the motion can be found easily by Principle of Energy Conservation by the fact that maximum elastic potential energy (U_{e}), in joules, is equal to maximum translational kinetic energy (K), in joules:

U_{e} = K

\frac{1}{2}\cdot k \cdot A^{2} = \frac{1}{2}\cdot m \cdot v^{2} (1)

Where:

k - Spring constant, in newtons per meter.

A - Amplitude, in meters.

m - Object mass, in kilograms.

v - Speed of the object at equilibrium, in meters per second.

If we know that k = 450\,\frac{N}{m}, m = 0.25\,kg and v = 0.3\,\frac{m}{s}, then the amplitude of the motion is:

\frac{1}{2}\cdot k \cdot A^{2} = \frac{1}{2}\cdot m \cdot v^{2}

k\cdot A^{2} = m\cdot v^{2}

A = v\cdot \sqrt{\frac{m}{k} }

A = \left(0.3\,\frac{m}{s} \right)\cdot \sqrt{\frac{0.25\,kg}{0.3\,\frac{m}{s} } }

A \approx 0.274\,m

The amplitude of the motion is approximately 0.274 meters.

2) The total energy of the object (E), in joules, is found either by maximum elastic potential energy or by maximum translational kinetic energy, that is: (k = 450\,\frac{N}{m}, A \approx 0.274\,m)

E = U_{e}

E = \frac{1}{2}\cdot k\cdot A^{2}

E = \frac{1}{2}\cdot \left(450\,\frac{N}{m} \right) \cdot (0.274\,m)^{2}

E = 16.892\,J

The total energy of the object at any point of its motion is 16.892 joules.

7 0
3 years ago
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