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finlep [7]
3 years ago
11

A store is having a sale on hats . The sale is buy one hat , get one 50% off . The original price of one is 24.98 . Alex bought

several hats . And the total cost is $187.34
Mathematics
1 answer:
Alex73 [517]3 years ago
3 0

50% of 24.98 = $12.49

24.98 + 12.49 = 37.47

187.34 / 37.47 = 5

5 x 2 hats = 10 hats

He bought 10 hats.

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What is the inverse of the function f(x) = x +3?
vladimir1956 [14]
The inverse of the function f(x)= x+3 would be x-3.
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3 years ago
The weights of the fish in a certain lake are normally distributed with a mean of 12 lb and a standard deviation of 12. If 16 fi
erastova [34]

Answer:

If 4 fish are randomly selected, what is the probability that the mean weight will be between 9.6 and 15.6 lb? Round your answer to four decimal places.

6 0
2 years ago
In a particular course, it was determined that only 70% of the students attend class on Fridays. From past data it was noted tha
siniylev [52]

Answer: Probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

Step-by-step explanation:

Since we have given that

Probability that students attend class on Fridays = 70% = 0.7

Probability that who went to class on Fridays would pass the course = 95% = 0.95

Probability that who did not go to class on Fridays would passed the course = 10% = 0.10

Let A be the event students passed the course.

Let E be the event that students attend the class on Fridays.

Let F be the event that students who did not attend the class on Fridays.

Here, P(E) = 0.70 and P(F) = 1-0.70 = 0.30

P(A|E) = 0.95,  P(A|F) = 0.10

We need to find the probability that they did not attend on Fridays.

We would use "Bayes theorem":

P(F\mid A)=\dfrac{P(F).P(A\mid F)}{P(E).P(A\mid E)+P(F).P(A\mid F)}\\\\P(F\mid A)=\dfrac{0.30\times 0.10}{0.70\times 0.95+0.30\times 0.10}\\\\P(F\mid A)=\dfrac{0.03}{0.695}=0.043

Hence, probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

8 0
3 years ago
Andrea played 8 games at the arcade and won 20 tickets to spend on prizes . How many games of basketball will Andre play to get
V125BC [204]

Answer:

If Andrea plays eight games at the arcade and wins 20 tickets per game then 8 x 20= 160.

If Andrea plays nine games at the arcade and wins 20 tickets per game then 9×20 = 180.

A= 9 games

Step-by-step explanation:

7 0
3 years ago
ik this is a lot but it’s due at 9am (yes ik i have a lot of accounts) but i’m failing and i’ll mark someone as brainliest and y
cluponka [151]

Answer:

1. 8x

2. 3x

3. 14x

4. 12x

5. 11x

6. 11x

7. 7x + 2

8. 16x +3

9.8x+5

10.9x + 4

11. 21x + 9

12. 7x + 8

Step-by-step explanation:

1. 8x

2. 3x

3. 14x

4. 12x

5. 11x

6. 11x

7. 7x + 2

8. 16x +3

9.8x+5

10.9x + 4

11. 21x + 9

12. 7x + 8

4 0
3 years ago
Read 2 more answers
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