Since the second equation gives a value for a, we can substitute it into the other equation to find a value for B.
Let's substitute b-2 into the first equation wherever there is an a.
a - 3b = 4
(b-2) - 3b = 4
b - 2 - 3b = 4
-2 - 2b = 4
-2b = 6
b = -3
Now let's find a by substituting -3 into either of the equations to find the value of a.
a = b - 2
a = -3 - 2
a = -5
So your solution set is (-5, -3)
Answer:
(a) There are two complex roots
Step-by-step explanation:
The discriminant of a quadratic function describes the nature of its roots:
- <u>negative</u>: two complex roots
- <u>zero</u>: one real root (multiplicity 2)
- <u>positive</u>: two distinct real roots.
__
Your discriminant of -8 is <em>negative</em>, so it indicates ...
There are two complex roots
_____
<em>Additional comment</em>
We generally study polynomials with <em>real coefficients</em>. These will never have an odd number of complex roots. Their complex roots always come in conjugate pairs.
14(4)÷(7)+5(17)-3 please help
218
