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monitta
3 years ago
8

Which of the following is a result of shifting a circle with equation (x - 5)^2 + (y - 6)^2 = 36 to the right 2 units?

Mathematics
2 answers:
Korvikt [17]3 years ago
6 0
C. The x-coordinate of the center of the circle increases by 2.
Because the equation of a circle is:
(x-h)^2 + (y-k)^2 = r^2, where the center of the circle is at (h, k), and the radius of the circle = r
So the center of this circle is at (5, 6).
To shift it to the right 2 units means to make the center 5+2=7, with no change in y or r.
Furkat [3]3 years ago
5 0
Recall,

Circle centered at (h,k) and radius r --

(x-h)^2+(y-k)^2=r^2

Here it is a circle centered at (h,k)=(5,6) and radius r=6
If you move to the right, the x coordinate will increase, so here the only change is the x coordinate increases by 2.
(x-5)^2+(y-6)^2=r^2
(x-7)^2+(y-6)^2=6^2
 
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The answer would be 2.9 million is the population of the city in 1990 and 0.08 million is the increase per year in the population.

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4 0
3 years ago
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3 years ago
What’s is the difference between an improper fraction and mixed number
Darya [45]

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An improper fraction is always 1 or greater than 1. And, finally, a mixed number is a combination of a wholenumber and a proper fraction.In a proper fraction, the numerator is always less than the denominator. Examples ofproper fractions include and 

6 0
3 years ago
2y/5y cube + 4y square + 6y
timama [110]

Answer:

here down is the answer

(2y/5y)^3+4y^2+6y

8y^3/125y^3 +16y^2+6y

8/125+16y^2+6y

8/125+16y^2+6y=0

16y^2+6y+8/125=0

it is in the form of quadratic equation

formula :

x=(-b+-square root of b^2-4ac) /2a

here a=16,b=6&c=8/125

x=(-b+-square root of b^2-4ac)/2a

x=(-6+-square root of 36-4.09)/2a here 4.09 came by calculation

x=(-6+-31.91)/2

so

x=(-6+31.91)/2 first (+);

x=25.91/2

x=12.955;

x=(-6-31.91)/2 then(-);

x=-37.91/2

x=-18.955 ;

ans is = 12.955&-18.955;

6 0
3 years ago
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