1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
rewona [7]
3 years ago
6

Ross chose a card at random from a deck of 52 cards. Ross replaced the card and then chose a second card. What is the probabilit

y that Ross chose a club and then the ace of spades?
Mathematics
1 answer:
DaniilM [7]3 years ago
8 0

Answer:

\frac{1}{208}

Step-by-step explanation:

We have been given that Ross chose a card at random from a deck of 52 cards. Ross replaced the card and then chose a second card.

Let us find probability of getting a club.

\text{ Probability of getting a club}=\frac{13}{52} =\frac{1}{4}

Now let us find probability of getting the ace of spades.

\text{ Probability of getting ace of spades}=\frac{1}{52}

Now let us multiply these to find probability of getting a club and ace of spades.      

\text{ Probability of getting a club and then ace of spades}=\frac{1}{4}*\frac{1}{52}=\frac{1}{208}

Therefore, probability of getting a club and then the ace of spades \frac{1}{208}.

You might be interested in
Please help!! asap!!! ( 10 points)
MAXImum [283]

Answer:

......................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................

Step-by-step explanation:

5 0
3 years ago
Simplify the expression by combining like terms. 22+5−4+7−8
nikklg [1K]

Answer:

22

Step-by-step explanation:

27-4+7-8=

23+7-8=

30-8=

22

3 0
3 years ago
How am i supposed to make a function? Number 15
Greeley [361]

Part A

<h3>Answer: T(n) = 58n+1800</h3>

-------------

Work Shown:

1800 = initial cost or starting cost

58*1 = 58 = cost for one person

58*2 = 116 = cost for two people

58*n = cost for n people

58n+1800 = total cost

58n+1800 = T(n)

T(n) = 58n+1800

======================================

Part B

<h3>Answer: D(T) = 0.85T</h3>

-------------

Work Shown:

T = total bill

15% discount means you still pay 85% of the bill (85%+15% = 100%)

D = discounted cost

D = 85% of T

D = 0.85*T

======================================

Part C

<h3>Answer: D(T(n)) = 49.3n + 1530</h3><h3>See attached image below for the table.</h3>

-------------

Work Shown:

We combine parts A and B.

T(n) = 58n+1800 from part A

D(T) = 0.85*T from part B

D(T(n)) = 0.85*( T(n) )

D(T(n)) = 0.85*( 58n+1800 ) ... plug in T(n) = 58n+1800

D(T(n)) = 0.85*( 58n+1800 )

D(T(n)) = 0.85*(58n)+0.85*(1800) ... distribute

D(T(n)) = 49.3n + 1530

If we plugged in n = 0, then,

D(T(n)) = 49.3n + 1530

D(T(0)) = 49.3*0 + 1530

D(T(0)) = 1530

Or we could plug n = 0 into T(n) to get T(0) = 1800

Then plug T = 1800 into D(T) = 0.85*T to get D(1800) = 1530

Either way you'll get the same answer.

Repeat this (using either method) for n = 50, 100, 150, 200 and you'll get the table of values you see below in the attached image.

======================================

Part D

The D( T(n) ) function allows us to find the discounted cost D for any number n of people that show up.

The input is n, where n is some positive integer less than or equal to 200 (because this is the reception hall's max capacity).

The output is the final discounted cost.

Example: n = 50 is one input which leads to its corresponding output of D( T(n) ) = 3995 as the table shows. So 50 people would have a discounted total cost of $3,995.

5 0
3 years ago
Can someone answer this question please?
Mekhanik [1.2K]
Steps:
1. calculate the values of y at x=0,1,2. using y=5-x^2
2. calculate the areas of trapezoids (Bottom+Top)/2*height
3. add the areas.

1. 
x=0, y=5-0^2=5
x=1, y=5-1^2=4
x=2, y=5-2^2=1
2. 
Area of trapezoid 1 = (5+4)/2*1=4.5
Area of trapezoid 2 = (4+1)/2*1=2.5

Total area of both trapezoids = (4.5+2.5) = 7

Exact area by integration:
integral of (5-x^2)dx   from 0 to 2
=[5x-x^3/3] from 0 to 2
=[5(2-0)-(2^3-0^3)/3]
=10-8/3
=22/3
=7 1/3, slight greater than the estimation by trapezoids.

8 0
3 years ago
Mr. Penn wants to buy pencils and erasers for the students in his class. If pencils come in packs of 20 and erasers in packs of
joja [24]
5 packs of erasers and 3 packs of pencils each will have 60
4 0
3 years ago
Other questions:
  • What is the answer to this? a=v-I/t
    12·1 answer
  • Tickets to a play cost $11 each. There is also a service charge of $4 per order. Write an equation for the relationship that giv
    14·2 answers
  • A birthday cake was cut into equal pieces, and nine pieces were eaten. The fraction below shows how many pieces are left. Accord
    6·1 answer
  • Pls help me with this  11-3 and 11-4 u press the link below 
    8·1 answer
  • 40 points help me please
    6·2 answers
  • Please help i will mark brainliest
    12·2 answers
  • Just read the picture and thats the question
    10·1 answer
  • DO NOT SEND ME LINKS OR PDFS I WILL REPORT ANSWER CORRECTLY TO GET BRAINLIEST
    6·1 answer
  • Pls help :) not understanding this thank you!!!
    5·1 answer
  • Write an equation that expresses the following relationship.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!