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pantera1 [17]
3 years ago
9

For the cost function, find the marginal cost at the given production level x. State the units of measurement. (All costs are in

dollars.) HINT [See Example 1.] C(x) = 15,000 + 50x + 1,000 x ; x = 100
Mathematics
1 answer:
baherus [9]3 years ago
6 0

Answer:

The marginal cost at the given production level is $49.9.

Step-by-step explanation:

The marginal cost function is expressed as the first derivative of the total cost function with respect to quantity (x).

We have that the cost function is given by

C(x) = 15000 + 50x + \frac{1000}{x}

So, we need the derivative and then we’ll need to compute the value x = 100 of the derivative.

C'(x)=\frac{d}{dx}\left(15000+50x+\frac{1000}{x}\right)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\C'(x)=\frac{d}{dx}\left(15000\right)+\frac{d}{dx}\left(50x\right)+\frac{d}{dx}\left(\frac{1000}{x}\right)\\\\C'(x)=0+50-\frac{1000}{x^2}\\\\C'(x)=50-\frac{1000}{x^2}

When x = 100, the marginal cost is

C'(100)=-\frac{1000}{100^2}+50\\\\C'(100)=\frac{499}{10}=49.9

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X^2 - y^2 = 100
luda_lava [24]

Answer:

20

Step-by-step explanation:

Let's start by rewriting the second equation in terms of "x":

x+y=5

Subtract y from both sides:

x=5-y

Now, substitute "5-y" for "x" in the first equation:

(5-y)^2-y^2=100

Note that:

(a-b)^2=a^2-2ab+b^2

25-10y+y^2-y^2=100

Cancel out like terms:

25-10y=100

Subtract 25 from both sides:

-10y=75

Divide both sides by -10

y=\frac{75}{-10}=\frac{15}{-2}=-\frac{15}{2}

Now, substitute this value back into either of the equations to solve for x.

x+y=5\\x-\frac{15}{2}=5\\

Add 15/2 to both sides:

x=5+\frac{15}{2}\\x=\frac{10}{2}+\frac{15}{2}\\x=\frac{25}{2}

Now, find the difference:

x-y=\frac{25}{2}-(-\frac{15}{2})=\frac{25}{2}+\frac{15}{2}=\frac{40}{2}=20

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2 years ago
I need help with all three letters. thank u
creativ13 [48]

Answer:

Step-by-step explanation:

A to C

y = b + mx

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Looking at the line, the line crosses the y-axis at the coordinates (0,0). This means that the y-intercept is 0.

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Looking back we can see that our variables now have value so we can plug them into our formula.

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Step-by-step explanation:

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