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adell [148]
3 years ago
13

How do I get my answer

Mathematics
1 answer:
kupik [55]3 years ago
5 0

Answer:

i think it is 5/8    6/12    3/4

Step-by-step explanation:


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What is the sum of 1+2+.....+50?​
Natasha_Volkova [10]

Answer:

<u>sum</u><u> </u><u>is</u><u> </u><u>1</u><u>2</u><u>7</u><u>5</u>

Step-by-step explanation:

sum =  \frac{n}{2} [2a + (n - 1)d] \\  \\ sum =  \frac{50}{2} [(2 \times 1) + (50 - 1) \times 1] \\  \\ sum = 25(51) \\ sum = 1275

7 0
3 years ago
Y = 7/2x + 10 y = -7/2x - 1/10 these lines have perpendicular slopes. True or false?
forsale [732]

Answer: This is False because they don't go together and it doesn't make sense.

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Você tem $ 20 para gastar com o táxi. A corrida custa $5 mais $2,50d 2,50 por quilômetro.
Aloiza [94]

Answer:

$5 + 2.50k ≤ $20

6 kilometers

Step-by-step explanation:

Puedes viajar con $15 porque gastaste 5 en la tarifa base. 15 dividido por 2,5 es 6, por lo que puedes viajar 6 kilómetros con $20.

5 0
1 year ago
2x − y = −4→10x − 5y = −20 3x 5y = 59→3x 5y = 59 13x = 39 which equation can replace 3x 5y = 59 in the original system and still
malfutka [58]
13x = 39 can replace 3x + 5y = 59 in the original system and still produce the same solution.
8 0
3 years ago
Suppose a research firm conducted a survey to determine the average amount of money steady smokers spend on cigarettes during a
olchik [2.2K]

Answer:

option (b) 0.0228

Step-by-step explanation:

Data provided in the question:

Sample size, n = 100

Sample mean, μ = $20

Standard deviation, s = $5

Confidence interval = between $19 and $21

Now,

Confidence interval = μ ± z\frac{s}{\sqrt n}

thus,

Upper limit of the Confidence interval = μ + z\frac{s}{\sqrt n}

or

$21 =  $20 + z\frac{5}{\sqrt{100}}

or

z = 2

Now,

P(z = 2) = 0.02275                       [From standard z vs p value table]

or

P(z = 2) ≈ 0.0228

Hence,

the correct answer is option (b) 0.0228

3 0
2 years ago
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