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3 years ago

1/2(10x+20y+10z help me please

Mathematics

2 answers:

den301095 [7]3 years ago

6 0

Given is 1/2(10x+20y+10z)

Simplifying the given expression using Algebra properties.

$\frac{1}{2} (10x+20y+10z) \\\\Step \;1: \;Using \;Distribution \;property \\\\=\frac{10x}{2}+ \frac{20y}{2}+ \frac{10z}{2} \\\\Step \;2: \;Dividing \\\\=5x+10y+5z \\\\Step \;3: \;Factoring \;out \;common \;factor \\\\= 5*(x+2y+z)$

Hence, the final answer would be (5x + 10y + 5z) or 5·(x + 2y + z).

kupik [55]3 years ago

4 0

Answer:

(5x+10y+5z)

Step-by-step explanation:

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Please help! I will mark as brainliest IF answer is right. <3

kramer

Step-by-step explanation:

Domain x belongs to [-4 , 0]

Range y belongs to [-4 , 4]

6 0

3 years ago

The sum of a number and 8 is larger than the difference of the number and 10. (Use x to represent the number)

LiRa [457]

Answer:

Step-by-step explanation:

it is talkin about 2

8 + 2 = 10

10 - 2 = 8

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3 years ago

Prove that : sinA/1+cosA + 1+cosA/sinA=2cosecA

tekilochka [14]

Step-by-step explanation:

$\frac{sinA}{1+cosA} +\frac{1+cos}{sinA} =2cosec\\\\\\\frac{sin^{2}A+(1+cos)^{2} }{sinA(1+cosA)} \\\\$

$\frac{sin^{2}A+1+cos^{2}+2cos}{sinA(1+cosA)} \\\\$ and we have $sin^{2}+cos^{2} =1$

so $\frac{1+1+2cosA }{sinA(1+cosA)} \\\\$

$\frac{2+2cosA }{sinA(1+cosA)} \\\\$

$\frac{2(1+cosA)}{sinA(1+cosA)} \\\\$

$\frac{2}{sinA}$ we have $\frac{1}{sin}=cosec\\$

Finally $2cosecA$

I really hope this helps coz it took much time

3 0

3 years ago

Please help me find the answer pls

fiasKO [112]

Answer:

A. Solutions are: x = 2, y = 1.

B. Solutions are: x = 3, y = 2.

1. Inconsistent

2. Inconsistent

3. Consistent

Step-by-step explanation:

A. Solutions of each system of linear equations by substitution method:

Equation 1: 3x - 2y = 4

Equation 2: x = 2y

Step 1: Substitute x = 2y into the Equation 1:

3(2y) - 2y = 4

6y - 2y = 4

4y = 4

Step 2: Divide both sides of the equation by 4 to isolate y:

$\frac{4y}{4} = \frac{4}{4}$

y = 1.

Step 3: For Equation 2, x = 2y, substitute y = 1 into the equation to solve for x:

x = 2y

x = 2(1)

x = 2

Therefore, the solutions are: x = 2, y = 1.

B. Find the solutions of each system of linear equations by elimination method:

Equation 1: 2x + y = 8

Equation 2: x + y = 5

Step 1: Multiply Equation 2 by 2:

2(x + y) = 5(2)

2x + 2y = 10

Step 2: Subtract Equation 1 from the equation derived from Step 1, 2x + 2y = 10:

2x + 2y = 10

- 2x + y = 8

y = 2

Step 3: Plug in y = 2 into Equation 1, 2x + y = 8 to solve for x:

2x + y = 8

2x + (2) = 8

Step 4: subtract both sides of the equation by 2 to isolate x:

2x + 2 - 2 = 8 - 2

2x = 6

Step 5: Divide both sides of the equation by 2 to solve for x:

$\frac{2x}{2} = \frac{6}{2}$

x = 3.

The solutions are: x = 3, y = 2.

1. Inconsistent

2. Inconsistent

3. Consistent (infinitely many solutions)

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3 years ago

What is quarter past 3

svetlana [45]

What is quarter pass 3 your answer would be 3:45

7 0

3 years ago

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