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3 years ago

Py+7=6y+q what is the answer for this question (linear equations with unknown coefficients)?

Mathematics

2 answers:

Temka [501]3 years ago

3 0

Assuming your solving for y:
py+7=6y+q
-6y -7 -6y -7
(p-6)y = q-7
divide both sides by p-6
y=(q-7)/(p-6)

kompoz [17]3 years ago

3 0

Answer:

The required equation is $y =\frac{(q-7)}{(p-6)}$ .

Step-by-step explanation:

Consider the provided equation.

$py+7=6y+q$

We need to simplify the equation and convert it into a linear equation with unknown coefficients.

Subtract 6y from both sides.

$py - 6y + 7 = q$

Subtract 7 from both sides.

$py - 6y = q - 7$

Take y common from left side.

$y(p-6) = q-7$

Divide both sides by p-6.

$y =\frac{(q-7)}{(p-6)}$

Hence, the required equation is $y =\frac{(q-7)}{(p-6)}$ .

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Tc = fixed cost + variable cost

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Answer:

These correspond to two types of cost: fixed cost and variable cost. Fixed cost (FC): the cost of all fixed inputs in a production process. Another way of saying this: production costs that do not change with the quantity of output produced. Variable cost (VC): the cost of all variable inputs in a production process.

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3 years ago

Solve x to the second power = 144

vfiekz [6]

x ^ 2 = 144

x = 12, x = -12

Check:

12 * 12 = 144

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3 years ago

Read 2 more answers

A consumer products company is formulating a new shampoo and is interested in foam height (in mm). Foam height is approximately

Genrish500 [490]

Answer:

a) 0.057

b) 0.5234

c) 0.4766

Step-by-step explanation:

To find the p-value if the sample average is 185, we first compute the z-score associated to this value, we use the formula

$z=\frac{\bar x-\mu}{\sigma/\sqrt N}$

where

$\bar x=mean\; of\;the \;sample$

$\mu=mean\; established\; in\; H_0$

$\sigma=standard \; deviation$

N = size of the sample.

So,

$z=\frac{185-175}{20/\sqrt {10}}=1.5811$

$\boxed {z=1.5811}$

As the sample suggests that the real mean could be greater than the established in the null hypothesis, then we are interested in the area under the normal curve to the right of 1.5811 and this would be your p-value.

We compute the area of the normal curve for values to the right of 1.5811 either with a table or with a computer and find that this area is equal to 0.0569 = 0.057 rounded to 3 decimals.

So the p-value is

$\boxed {p=0.057}$

Since the z-score associated to an α value of 0.05 is 1.64 and the z-score of the alternative hypothesis is 1.5811 which is less than 1.64 (z critical), we cannot reject the null, so we are making a Type II error since 175 is not the true mean.

We can compute the probability of such an error following the next steps:

Step 1

Compute $\bar x_{critical}$