Answer:
1. Mass = 2070 kg
2.Total length of strip = 2556 m
3. Total length of dislocation = 7.67 X m
Explanation:
Given:
Aluminium coil thickness, t = 0.3 mm
= 0.3 X m
Width of the coil,w = 1 m
Drum diameter, d = 15 cm
= 0.15 m
Coil outer diameter, d = 1 m
Dislocation density =
1). Area of the coil, A = ( -)
A =
A = 0.767
Volume of the coil,V = A X w
= 0.767 X 1
= 0.767
We know density of aluminum at STP = 2.7 X
Therefore, mass of the aluminum coil is,
Mass,m = Density of aluminium X Volume
= 2.7 X X 0.767
= 2070 kg
Mass = 2070 kg
2). Total length of trip of coil is given by
L = Volume of coil / area of strip
=
= 2556 m
Total length of strip = 2556 m
3). Total length of dislocation of the coiled strip = volume X dislocation density
= 0.767 X
= 7.67 X
Total length of dislocation = 7.67 X m