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3 years ago

LEARNING ACTIVITY SHEET

Engineering

1 answer:

Nady [450]3 years ago

3 0

Answer:

1. It is used to test/check the continuity of the circuit

a. Ohmmeter

2. Is a physical device used to connect electronic test equipment to a device under test

a. Test probes

3. A device inserted to a convenience outlet to conduct electric current

a. Plug

4. Is a stranded wire used to temporary wiring installation and commonly used in extension cord assembly

a. Duplex cord

5. It is a pocket size tool used to test the line wire or circuit if there is a current in it.

a. Test light

6. An instrument used to measure the amount of electrical current intensity in a circuit

b. Ammeter

7. A pocket sized tool used to test the line wire or circuit if there is current in it.

a. Test light

8. A measuring tool used to measure the length of an object in centimeter in it

b) Ruler

9. It is used to measure the diameter of wires/conductors in circular mills. It can measure small and big sizes of wires

a. Micrometer

10. It is used to measure the voltage, resistance and current of a circuit. It is connected in parallel or series with the circuit depending on what to measure

a) Volt-Ohm-milliammeter

11. It is the measuring tool used to measure length, width and thickness of short object and in sketching straight line

Foot rule/ ruler

Explanation:

1. An Ohmmeter tests resistance of a circuit and therefore, indicates if the circuit has continuity (connectivity) by measuring the resistance to the current it sends through the circuit, while the circuit power is switched off

2. A test probe connects a testing equipment to a Device Under Test (DUT)

3. A plug is used to connect an electric appliance to the mains power supply by fitting it into the mains power outlet

4. A duplex cord is used for temporary wiring to supply power in an extension cord assembly

5. A test light is used to determine if a circuit has electric current flowing in it

6. An ammeter measures the amount of direct or alternating current flowing in a circuit

7. Test light is used to check the presence of an electric current in a circuit

8. A ruler is used to measure length and it is marked in cm or in

9. A micrometer measures the diameter of wires placed in between the anvil and spindle

10. A Volt-Ohm-Milliammeter (VOM), is also known as a multimeter that measures voltage, current, and resistance of a circuit

11. A foot rule/ ruler, measures the dimensions of objects that are flat and short

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Sea water with a density of 1025 kg/m3 flows steadily through a pump at 0.21 m3 /s. The pump inlet is 0.25 m in diameter. At the

myrzilka [38]

Answer:

$\dot W_{pump} = 16264.922\,W\,(16.265\,kW)$

Explanation:

The pump is modelled after applying Principle of Energy Conservation, whose form is:

$\frac{P_{1}}{\rho\cdot g}+ \frac{v_{1}^{2}}{2\cdot g} +z_{1} + h_{pump}=\frac{P_{2}}{\rho\cdot g}+ \frac{v_{2}^{2}}{2\cdot g} +z_{2}$

The head associated with the pump is cleared:

$h_{pump} = \frac{P_{2}-P_{1}}{\rho\cdot g}+\frac{v_{2}^{2}-v_{1}^{2}}{2\cdot g}+(z_{2}-z_{1})$

Inlet and outlet velocities are found:

$v_{1} = \frac{0.21\,\frac{m^{3}}{s} }{\frac{\pi}{4}\cdot (0.25\,m)^{2} }$

$v_{1} \approx 4.278\,\frac{m}{s}$

$v_{2} = \frac{0.21\,\frac{m^{3}}{s} }{\frac{\pi}{4}\cdot (0.152\,m)^{2} }$

$v_{2} \approx 11.573\,\frac{m}{s}$

Now, the head associated with the pump is finally computed:

$h_{pump} = \frac{175\,kPa-81.326\,kPa}{(1025\,\frac{kg}{m^{3}} )\cdot (9.807\,\frac{m}{s^{2}} )} +\frac{(11.573\,\frac{m}{s} )^{2}-(4.278\,\frac{m}{s} )^{2}}{2\cdot (9.807\,\frac{m}{s^{2}} )} + 1.8\,m$

$h_{pump} = 7.705\,m$

The power that pump adds to the fluid is:

$\dot W_{pump} = \dot V \cdot \rho \cdot g \cdot h_{pump}$

$\dot W_{pump} = (0.21\,m^{3})\cdot (1025\,\frac{kg}{m^{3}})\cdot (9.807\,\frac{m}{s^{2}})\cdot(7.705\,m)$

$\dot W_{pump} = 16264.922\,W\,(16.265\,kW)$

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3 years ago

15- Vipsana's Gyros House sells gyros. The cost of ingredients (pita, meat, spices, etc.) to make a gyro is $2.00. Vipsana pays

sineoko [7]

D is a great answer

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3 years ago

Air is pumped from a vacuum chamber until the pressure drops to 3 torr. If the air temperature at the end of the pumping process

malfutka [58]

Answer:

The final pressure is 3.16 torr

Solution:

As per the question:

The reduced pressure after drop in it, P' = 3 torr = $3\times 0.133\ kPa$

At the end of pumping, temperature of air, $T = 5^{\circ}C = 278 K$

After the rise in the air temperature, $T' = 20^{\circ}C = 293 K$

Now, we know the ideal gas eqn:

PV = mRT

$P = \frac{m}{V}RT$

$P = \rho_{a}RT$ (1)

where

P = Pressure

V = Volume

$\rho_{a} = air\ density$

R = Rydberg's constant

T = Temperature

Using eqn (1):

$P = \rho_{a}RT$

$\rho_{a} = \frac{P}{RT}$

$\rho_{a} = \frac{3 times 0.133\times 10^{3}}{0.287\times 278} = 0.005 kg/m^{3}$

Now, at constant volume the final pressure, P' is given by:

$\frac{P}{T} = \frac{P'}{T'}$

$P' = \frac{P}{T}\times T'$

$P' = \frac{3}{278}\times 293 = 3.16 torr$

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4 years ago

a valueable preserved biological specimen is weighed by suspeding it from a spring scale. it weighs 0.45 N when it is suspendedi

Dmitry_Shevchenko [17]

Answer:

ρ=962.16kg/m^3

Explanation:

The first thing we must do to solve is to find the mass of the specimen using the weight equation

w = mg

m=w/g

m=0.45/9.81=0.04587kg

To find the volume we must make a free-body diagram on the specimen, taking into account that the weight will go down and the buoyant force up, and the result of that subtraction will be the measured weight value (0.081N).

We must bear in mind that the principle of archimedes indicates that the buoyant force is given by

F = ρgV

where V is the specimen volume and ρ is the density of alcohol = 789kg / m ^ 3

considering the above we have the following equation

0.081=0.45-(789)(9.81m/s^2)V

solving for V

V=(0.081-0.45)/(-789x9.81)

V=4.7673x10^-5m^3

finally we found the density

ρ=m/v

ρ=0.04587kg/4.7673x10^-5m^3

ρ=962.16kg/m^3

4 0

4 years ago