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Phoenix [80]
3 years ago
8

Quelle est la transformée de Laplace inverse de 2 ?

Engineering
1 answer:
aev [14]3 years ago
4 0

Answer: Tenga en cuenta que sinh3 = 3 − − 32 sinh 3t = mi 3 t - mi - 3 t 2 Por eso, 2sinh3 = 4 − − 2

Explanation:

he hecho esto antes

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I am in 6th grade, why are high school things popping up??

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These tadpoles are confined to a limited environment. What are they all competing for in that environment
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A rigid tank contains an ideal gas at 40°C that is being stirred by a paddle wheel. The paddle wheel does 240 kJ of work on the
Sergeu [11.5K]

To solve the problem it is necessary to consider the concepts and formulas related to the change of ideal gas entropy.

By definition the entropy change would be defined as

\Delta S = C_p ln(\frac{T_2}{T_1})-Rln(\frac{P_2}{P_1})

Using the Boyle equation we have

\Delta S = C_p ln(\frac{T_2}{T_1})-Rln(\frac{v_1T_2}{v_2T_1})

Where,

C_p = Specific heat at constant pressure

T_1= Initial temperature of gas

T_2= Final temprature of gas

R = Universal gas constant

v_1= Initial specific Volume of gas

v_2= Final specific volume of gas

According to the statement, it is an isothermal process and the tank is therefore rigid

T_1 = T_2, v_2=v_1

The equation would turn out as

\Delta S = C_p ln1-ln1

<em>Therefore the entropy change of the ideal gas is 0</em>

Into the surroundings we have that

\Delta S = \frac{Q}{T}

Where,

Q = Heat Exchange

T = Temperature in the surrounding

Replacing with our values we have that

\Delta S = \frac{230kJ}{(30+273)K}

\Delta S = 0.76 kJ/K

<em>Therefore the increase of entropy into the surroundings is 0.76kJ/K</em>

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A reservoir rock system located between a depth of 2153m and a depth of
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Ivan

Answer:

Use GitHub or stackoverflow for this answer

Explanation:

It helps with programming a lot

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