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Temka [501]
3 years ago
14

What is the product of 14 times 25 times 4 using the associative and communicative properties

Mathematics
1 answer:
andriy [413]3 years ago
4 0
1400 is you're answer because 25x14=350×4=1,400
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You are paid $38.25 for yard work and it took your 4.5 hours. How much did you earn<br> per hour?
Murljashka [212]

Answer:

8.5

Step-by-step explanation:

38.25/4.5

7 0
3 years ago
Please help! The volume of an inflated spherical water balloon is 121,500 pi millimeters to the third. What is the radius of the
irga5000 [103]

Answer:

The radius of the inflated spherical balloon  is 45 millimeters.

Step-by-step explanation:

Volume of the spherical water balloon = 121,500 pi  cubic millimeters

Let the radius of the balloon = r

Now, Volume of a Sphere = \frac{4}{3} \pi r^{3}

⇒\frac{4}{3} \pi r^{3}  = 121,500 \pi

On solving for the value of r, we get:

r^{3}  = \frac{121,500\times 3}{4}   = 91125\\ \implies  r  = \sqrt[3]{91125}

or, r  = 45 millimeter

Hence, the radius of the inflated spherical balloon  is 45 millimeters.

5 0
4 years ago
Given right triangle QRS, what is the value of sin(30°)? StartFraction StartRoot 3 EndRoot Over 3 EndFraction One-half StartFrac
baherus [9]

Answer:

Option 2: \sin(30)=\frac{1}{2}

Step-by-step explanation:

Given:

From the triangle shown below;

A triangle QRS with angle QRS = 90°, ∠QSR = 30°.

Side QR = 5, SQ = 10 and RS = 5√3

Now, we know from trigonometric ratio that,

\sin (A) = \frac{Opposite\ side}{Hypotenuse}

Here, opposite side of angle QSR is QR and Hypotenuse is the side opposite angle QRS which is SQ. Therefore,

\sin(\angle QSR)=\dfrac{QR}{SQ}\\\\\\\sin(30)=\dfrac{5}{10}\\\\\\\sin(30)=\dfrac{5}{2\times 5}=\dfrac{1}{2}

Therefore, the value of sine of 30° is one-half. So, second option is correct.

6 0
3 years ago
Read 2 more answers
Answer correctly please !!!!!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!!!!!!!!!
PtichkaEL [24]

Answer:

x = 118

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Suppose that a function​ f(x) is defined for all real values of x except at xequals=c. can anything be said about the existence
Margaret [11]

we are given that

f(x) is defined for all values of x except at x=c

Limit may or may not exist

case-1:

If there is hole at x=c , then limit exist

case-2:

If there is vertical asymptote at x=c , then limit does not exist

Examples:

case-1:

\lim_{x \to c} \frac{x^2-cx}{(x-c)}

We can simplify it

\lim_{x \to c} \frac{x(x-c)}{(x-c)}

=\lim_{x \to c} x

=c

so, we can see that limit exist and it's value defined

case-2:

\lim_{x \to c} \frac{1}{(x-c)}

Left limit is

\lim_{x \to c-} \frac{1}{(x-c)}

=-\infty

Right Limit is

\lim_{x \to c+} \frac{1}{(x-c)}

=+\infty

so, we can see that left limit is not equal to right limit

so, limit does not exist

4 0
3 years ago
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