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DerKrebs [107]
3 years ago
14

1. What is the length of the segment joining the points at (-1,6) and (-5,3) 2. What is the length of the segment joining the po

ints at (-4, 1) and (3,7)
Mathematics
1 answer:
Nuetrik [128]3 years ago
8 0
QUESTION 1

We want to find the length of the segment joining the points at (-1,6) and (-5,3).



We use the distance formula which is given by the formula,

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}


d=\sqrt{( - 5 -  - 1)^2+(3 - 6))^2}


d=\sqrt{( - 5  + 1)^2+(3 - 6)^2}



d=\sqrt{( - 4)^2+( - 3)^2}


d=\sqrt{16+9}


d=\sqrt{25}

d = 5 \: units


QUESTION 2

We want to find the length of the segment joining at (-4,1) and (3,7).




We use the distance formula to get,


d =  \sqrt{(3 -  - 4)^{2}  +  {(7 - 1)}^{2} }

d =  \sqrt{(3  + 4)^{2}  +  {(7 - 1)}^{2} }




d =  \sqrt{7^{2}  +  {6}^{2} }


d =  \sqrt{49+  36 } .


d =  \sqrt{85 }  \: units
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DIA [1.3K]

Answer:

We note that the equation that is compatible with the given equation is the kinematic equation of free fall where;

t² = 39.2 × 2/9.81

From which we have;

The time it takes the snowball to reach the ground is approximately 2.83 seconds

Step-by-step explanation:

The height of the building from which the ball is dropped, h = 39.2 m

The equation of the dropped a snowball, is given as follows;

t² = 39.2 × 9.8

Using the From the equation of free fall, we have;

s = u·t + 1/2·g·t²

Where;

u = The initial velocity = 0 m/s

t = The time of flight

g = The acceleration due to gravity = 9.81 m/s²

Therefore, we get;

∴ s = The height from which the snowball is dropped = 39.2 m

Therefore, we get;

39.2 = 0×t + 1/2×9.81×t²

∴ t² = 39.2 × 2/9.81  ≈ 7.99

t = √(7.99) ≈ 2.83

The time it takes the snowball to reach the ground, t ≈ 2.83 s.

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Find the slope of the line shown on the graph to the right.Select the correct choice below and fill in any answer boxes within y
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1 year ago
Help Please!?
swat32
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Answer:

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Then do some sums...

Explanation:

<span><span><span>f<span>(x)</span></span>=−3<span>x4</span>−5<span>x3</span>−<span>x2</span>−8x+4</span> </span>

Since there is one change of sign, <span><span>f<span>(x)</span></span> </span> has one positive zero.

<span><span><span>f<span>(−x)</span></span>=−3<span>x4</span>+5<span>x3</span>−<span>x2</span>+8x+4</span> </span>

Since there are three changes of sign <span><span>f<span>(x)</span></span> </span> has between <span>1 </span> and <span>3 </span> negative zeros.

Since <span><span>f<span>(x)</span></span> </span> has Real coefficients, any non-Real Complex zeros will occur in conjugate pairs, so <span><span>f<span>(x)</span></span> </span> has exactly <span>1 </span> or <span>3 </span> negative zeros counting multiplicity, and <span>0 </span> or <span>2 </span> non-Real Complex zeros.

<span><span>f'<span>(x)</span>=−12<span>x3</span>−15<span>x2</span>−2x−8</span> </span>

Newton's method can be used to find approximate solutions.

Pick an initial approximation <span><span>a0</span> </span>.

Iterate using the formula:

<span><span><span>a<span>i+1</span></span>=<span>ai</span>−<span><span>f<span>(<span>ai</span>)</span></span><span>f'<span>(<span>ai</span>)</span></span></span></span> </span>

Putting this into a spreadsheet and starting with <span><span><span>a0</span>=1</span> </span> and <span><span><span>a0</span>=−2</span> </span>, we find the following approximations within a few steps:

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We can then divide <span><span>f<span>(x)</span></span> </span> by <span><span>(x−0.42)</span> </span> and <span><span>(x+2.195)</span> </span> to get an approximate quadratic <span><span>−3<span>x2</span>+0.325x−4.343</span> </span> as follows:

Notice the remainder <span>0.013 </span> of the second division. This indicates that the approximation is not too bad, but it is definitely an approximation.

Check the discriminant of the approximate quotient polynomial:

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Since this is negative, this quadratic has no Real zeros and we can be confident that our original quartic has exactly <span>2 </span> non-Real Complex zeros, <span>1 </span> positive zero and <span>1 </span> negative one.

3 0
4 years ago
Subtracting a negative number from a negative number gives you what
GREYUIT [131]
Depends.
A. -12 - -6 = -6
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-12+6, and B. -6+12.

8 0
3 years ago
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