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AlekseyPX
3 years ago
7

Im boing exam help please In a category-based course grading system, teachers weigh a student's performance in all courses. all

categories equally. some categories more heavily than others. extra credit as a bonus.
Computers and Technology
2 answers:
ycow [4]3 years ago
7 0

Answer:

some categories more heavily than others.

Explanation:

A category-based course grading system is a form of a grading system that involves an examiner to set up different categories of the overall assessment and at the same time placed different weight or marks over each category.

Therefore, the examiners weigh a student's performance in " some categories more heavily than others." For example, an examiner placed different weight over different categories in the overall assessment

1. Homework category: 30%

2. Classwork category: 20%

3. Quiz category: 20%

4. Final exam category: 30%

svp [43]3 years ago
7 0

Answer:

B

Explanation:

You might be interested in
Add the following 2's complement binary numbers. Also express the answer in decimal. a. 01+ 1011b. 11+ 01010101c. 0101+ 110d. 01
kenny6666 [7]

Answer:

(a) 01 + 1011

Convert the two numbers into their 4-bit representation.

=> 01 = 0001

=> 1011

Addition of the two numbers (in their 2's complement form) gives the following:

0 0 0 1       ------------------> + 1 (in decimal)

<u>1  0 1  1 </u>      ------------------> - 5 (in decimal)

<u>1  1  0 0 </u>    -------------------> - 4 (in decimal)

Explanation for (a)

<em>01 or 0001</em>

Since the most significant bit is 0 (leftmost bit), it shows that it is a positive number. Therefore, it can be directly converted to its decimal representation as follows:

0001 = 0 x 2^{3} + 0 x 2^{2} + 0 x 2^{1} + 1 x 2^{0} = 1

0001 is + 1 in decimal.

<em>1011</em>

Its most significant bit(MSB) is 1 showing that it is negative.

Flipping all its bits and adding 1 to the result, will convert it to it's positive counterpart.

i.e 1011 => 0100 + 1 = 0101.

Converting the result (0101) to decimal gives

0101 = 0 x 2^{3} + 1 x 2^{2} + 0 x 2^{1} + 1 x 2^{0} = 5

1011 is -5 in decimal

<em>01 + 1011 or 0001+ 1011 = 1100</em>

The result (1100), of the addition of the two numbers, is a negative number as the MSB is 1.

Convert it to it's positive counterpart.

i.e 1100 => 0011 + 1 = 0100.

Converting the result (0100) to decimal gives

0100 = 0 x 2^{3} + 1 x 2^{2} + 0 x 2^{1} + 0 x 2^{0} = 4

Therefore, the result, 1100 is -4 in decimal.

===================================================

(b) 11 + 01010101

Convert the two numbers into their 8-bit representation since one of them is in 8-bit.

PS: Taking 11, its MSB is 1 showing that it is a negative number. Also, it's 8-bit representation will mean pre-padding it with ones(1s) rather than zeros as follows. In other words, pre-padding a 2's complement  number is done using its sign bit.

=> 11 = 11111111

=> 01010101

Addition of the two numbers (in their 2's complement form) gives the following:

  1  1  1  1  1  1  1  1       ------------------> - 1 (in decimal)

<u>   0 1  0 1  0  1 0 1 </u>      ------------------> + 85 (in decimal)

<u>1 0 1  0 1  0  1 0 0</u>    ------------------->  + 84 (in decimal)

Discard the carry-out bit (1) making the result 01010100

Explanation for (b)

<em>11 or 11111111</em>

Its MSB is 1 showing that it is negative.

Convert it to it's positive counterpart.

11111111 => 00000000 + 1 = 00000001

Converting the result (00000001) to decimal gives 1

11 or 11111111 is  - 1 in decimal.

<em>01010101</em>

Its MSB is 0 showing that it is also positive. Now, convert to decimal

01010101 = 85

01010101 is + 85 in decimal.

<em>11111111 + 01010101 = 01010100</em>

The result (01010100), is also positive as the MSB is 0. Now, convert to decimal.

01010100 = 84

Therefore the result (01010100) is + 84 in decimal.

===================================================

(c) 0101 + 110

Convert the two numbers into their 4-bit representations.

=> 0101 = 0101

=> 110 = 1110

Addition of the two numbers (in their 2's complement form) gives the following:

     0 1 0 1       ------------------> + 5 (in decimal)

<u>      1  1 1  0 </u>      -----------------> - 2 (in decimal)

<u>   1 0 0 1  1 </u>    -------------------> + 3 (in decimal)

Dicard the carry-out bit (leftmost bit) to get 0011 as result.

Explanation for (c)

<em>0101</em>

Since the MSB is 0 (leftmost bit), it shows that it is a positive number. Now, convert to decimal.

0101 =  5

0101 is +5 in decimal.

<em>110 or 1110</em>

Its MSB is 1 showing that it is negative.

Convert it to it's positive counterpart.

i.e 1110 => 0001 + 1 = 0010.

Converting the result (0010) to decimal gives

0010 =  2

1110 is -2 in decimal

<em>0101 + 110 = 0101+ 1110 = 0011</em>

The result (0011), is a positive number as the MSB is 0.

Converting the result (0011) to decimal gives

0011 = 3

Therefore, the result, 0011 is 3 in decimal.

===================================================

(d) 01 + 10

Convert the two numbers into their 4-bit representation.

=> 01 = 0001

=> 10 = 1110

Addition of the two numbers (in their 2's complement form) gives the following:

0 0 0 1       ------------------> + 1 (in decimal)

<u>1  1  1  0 </u>      ------------------> - 2 (in decimal)

<u>1  1  1  1 </u>    -------------------> - 1 (in decimal)

Explanation for (d)

<em>01 or 0001</em>

Since the MSB is 0 (leftmost bit), it shows that it is a positive number. Now convert to decimal.

0001 = 1

0001 is + 1 in decimal.

<em>1110</em>

Its MSB is 1 showing that it is negative.

Convert it to it's positive counterpart.

i.e 1110 => 0001 + 1 = 0010.

Converting the result (0010) to decimal gives

0010  = 2

1110 is -2 in decimal

<em>01 + 1011 or 0001+ 1110 = 1111</em>

The result (1111), is a negative number as the MSB is 1.

Convert it to it's positive counterpart.

i.e 1111 => 0000 + 1 = 0001.

Converting the result (0001) to decimal gives

0001 = 1

Therefore, the result, 1111 is -1 in decimal.

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When searching for your word processing file to finish writing your report, you should look for a file with which extension? (6
trasher [3.6K]

Answer:

doc

Explanation:

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Preparing for jobs that are high in demand allow you to...
quester [9]

Preparing for jobs that are high in demand allows an individual to focus their development of human capital on those careers.

Focus your development of human capital on those careers

<u>Explanation:</u>

As the demand for the job is high, there is no denying the fact that it will increase the likelihood of getting a job. It is a simple proportion, more the number of jobs, more are the chances of getting them.

Last but not least it will also allow an individual to be more attractive to employers in those fields. As an individual prepares for the job, they will acquire certain skills and knowledge that are capable of letting them being perceived as attractive.

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_______a file transfers a copy of the file from the storage media into your computer's memory?
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It's opening. I just took PF test (:
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