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lina2011 [118]
3 years ago
14

Use the drop-down menus to complete each equation so the statement about its solution is true.

Mathematics
1 answer:
disa [49]3 years ago
6 0

Answer:


Step-by-step explanation:

So,it would be easier to simplify the right equation, so when I say "the right equation", I mean the one I will make right now. It is 8x+9. So the first problem is 8x+9=x+?. Well, if there are no solutions, the slopes have to be the same, and the y-int doesn't matter. So the answer would be + 7x because that will make the x an 8x. If there is one solution, then the slope has to be different. So literally anything but 7x will work. Even constants. If there are infinitely many solutions, then the equations have to be the same. Meaning, you would have to add 7x and 9 to make the left equation the same as the right.

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2. It costs Edgar $2.65 one way to ride the bus to work. He uses the bus to go to and from work four days per week. He buys a bo
Maurinko [17]
$27

2.65 x 2 (since he has to go both to and from work each day) = $5.30
Add the daily cost of the water bottle (1.45) to make his total cost for one day, which is 6.75
Multiply this number by 4 (because he goes 4 days a week) to get $27 for one week.
6 0
3 years ago
A local shop sells frozen yogurt in four flavors. The yogurt comes in a small, medium, or large cup. A customer can top the yogu
Rasek [7]

Answer: 36 (maybe)

Step-by-step explanation:

For each sized cup, there is an option of 4 flavours. Which also have the option of 3 toppings

Example:

- Small - 1 - 3 toppings

              2 - 3

              3 - 3

              4 - 3

So 1 x 4 x 3 = 12

Since there is 3 cup sizes, multiply that by 3 = 36

Not sure if that's right but hope it helps somehow

7 0
4 years ago
Given: AD = BC and BCD = ADC <br> Prove: DE = CE
erastova [34]

Answer:

According to AD=BC So AC=BD

Step-by-step explanation:

AD = BC and angle ADC = angle BCD

we have to prove AC = BD

let's see ∆ADC and ∆BCD

AD = BC [ given ]

angle ADC = angle BCD [ given ]

CD = CD

from S - A - S

∆ADC congruence ∆BCD

3 0
4 years ago
Read 2 more answers
Find four consecutive positive integers such that the product of the first and fourth is four less than twice the first multipli
r-ruslan [8.4K]
Four consecutive integers... n, n+1, n+2, n+3.

The product of the 1st and 4th is four less than twice the 1st multiplied by the 4th.

n(n+3)=2n(n+3)-4  perform indicated multiplications...

n^2+3n=2n^2+6n-4  subtract n^2 from both sides

3n=n^2+6n-4  subtract 3n from both sides

n^2+3n-4=0  factor

n^2-n+4n-4=0

n(n-1)+4(n-1)=0

(n+4)(n-1)=0, and since n>0

n=1

So the four numbers are 1, 2, 3, 4

check...

1(4)=2(1)4-4

4=8-4

4=4
3 0
3 years ago
Simplify 5a-3a+2a<br> What is the answer
Nina [5.8K]

Answer:

10a

Step-by-step explanation:

4 0
3 years ago
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