Answer:
Value of boat = $23,400
Loss of value by boat per year = 8%
To find: - Monthly percent decrease in value of boat.
Solution: - Decrease of value per year = 8% of $23,400 = $1,872. Monthly decrease in value = $1,872/12 = $156. Monthly percentage decrease = ($156/$23,400) * 100 = 0.6667 or 0.67 (rounded to nearest hundredth)
Step-by-step explanation:
Answer:
x=-1
Step-by-step explanation:
so 3-2 is 1 right so what humber + 2 is 1 well -1 becasue -1 + 1 is 0 and plus 2 would be 1 so its -1 (or x= -1). Hope this helped!
Answer:
7.5 ft³/min
Step-by-step explanation:
Let x be the depth below the surface of the water. The height, h of the water is thus h = 10 - x.
Now, the volume of water V = Ah where A = area of isosceles base of trough = 1/2bh' where b = base of triangle = 4 ft and h' = height of triangle = 1 ft. So, A = 1/2 × 4 ft × 1 ft = 2 ft²
So, V = Ah = 2h = 2(10 - x)
The rate of change of volume is thus
dV/dt = d[2(10 - x)]/dt = -2dx/dt
Since dV/dt = 15 ft³/min,
dx/dt = -(dV/dt)/2 = -15 ft³/min ÷ 2 = -7.5 ft³/min
Since the height of the water is h = 10 - x, the rate at which the water level is rising is dh/dt = d[10 - x]/dt
= -dx/dt
= -(-7.5 ft³/min)
= 7.5 ft³/min
And the height at this point when x = 8 inches = 8 in × 1 ft/12 in = 0.67 ft is h = (10 - 0.67) ft = 9.33 ft
Answer:
a. $45.54; b. $51.42; c. See below
Step-by-step explanation:
a. 193 min
Service charge = $40.00
1st 100 min @ 0.021 = 2.10
Next 93 min @0.037 = <u> 3.44
</u>
Total = $45.54
b. 317 min
Service charge = $40.00
1st 100 min @ 0.021 = 2.10
2nd 100 min @ 0.037 = 3.70
117 min @ 0.048 = <u> 5.62</u>
Total = $51.42
c. Piecewise function
The charge is
- $40.00 + 0.021t if t ≤ 100
- $42.10 + 0.037(t - 100) if 100 < t ≤ 200
- $45.80 + 0.048 (t - 200) if t > 200
which we can write like this:
