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gladu [14]
2 years ago
11

Amara needs 4545 kilograms of meat to feed her 22 pet dragons each day. Each pet dragon eats the same amount of meat. How many k

ilograms of meat does Amara need to feed 44 pet dragons each day?
Mathematics
2 answers:
max2010maxim [7]2 years ago
3 0

Answer:

9090 kilograms

Step-by-step explanation:

To find the number of kilograms per dragon, we divide the amount of meat by the number of dragons.

4545/22  kilograms per dragon

Now we can multiply by the 44 dragon that she has.

4545/22 * 44 = 9090 kilograms

djverab [1.8K]2 years ago
3 0

Answer:

i believe your answer is 9090

Step-by-step explanation:


4545 =22 dragons each day

22 times 2=44

4545 times 2

9090

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A certain transportation system of buses and commuter trains is heavily utilized so that it is not practical to check every trav
IRINA_888 [86]

Answer:

0.0864 < p< 0.1358

We are confident (95%) that the true proportion of people admitted they did not buy a ticket is betwen 0.0864 and 0.1358.  

Step-by-step explanation:

1) Data given and notation  

n=621 represent the random sample taken    

X=69 represent the people admitted they did not buy a ticket

\hat p=\frac{69}{621}=0.111 estimated proportion of people admitted they did not buy a ticket

\alpha=0.05 represent the significance level (no given, but is assumed)    

z would represent the statistic

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A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

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The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

And replacing into the confidence interval formula we got:

0.111 - 1.96 \sqrt{\frac{0.111(1-0.111)}{621}}=0.0864

0.111 + 1.96 \sqrt{\frac{0.111(1-0.111)}{621}}=0.1358

And the 95% confidence interval would be given (0.0864;0.1358).

0.0864 < p< 0.1358

We are confident (95%) that the true proportion of people admitted they did not buy a ticket is betwen 0.0864 and 0.1358.  

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-6 is an extraneous solution.

Step-by-step explanation:

We can start by solving this problem.

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Next, we can subtract both sides by (x+10)

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Then, we can factor out the equation.

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Therefore, -6 is an extraneous solution.

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