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Given that the directrix is at y = 4 and the focus is at (0, -4), then the vertex is at (h, k) = (0, 0).
p is the distance between the vertex and the focus and between the vertex and the directrix = 4 and since the focus is below the directrix, p is negative, i.e. p = -4
Equation of a parabola is given by (x - h)^2 = 4p(y - k)
Therefore, the required equation is (x - 0)^2 = 4(-4)(y - 0)
x^2 = -16y
y = -1/16 x^2
Answer:
Step-by-step explanation:
Make denominators same:
Add the numerators:
Apply the rule:
Therefore,
Cancel out common factor of 2x+1:
<h3>
Answer:</h3>
y = (x +2)(x -1)(x -3) . . . . or . . . . y = x³ -2x² -5x +6
<h3>
Step-by-step explanation:</h3>
The graph shows y=0 at x=-2, x=1, and x=3. These are called the "zeros" or "roots" of the function, because the value of the function is zero there.
When "a" is a zero of a polynomial function, (x -a) is a factor. This means the factors of the graphed function are (x -(-2)), (x -1) and (x -3). The function can be written as the product of these factors:
... y = (x +2)(x -1)(x -3) . . . . . the equation represented by the graph
Or, the product can be multiplied out
... y = (x +2)(x² -4x +3)
... y = x³ -2x² -5x +6 . . . . . the equation represented by the graph
Answer:
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