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3 years ago

Can someone help me with this question?

Mathematics

1 answer:

KonstantinChe [14]3 years ago

8 0

-3. Put the two equation equal to each other and solve.
4x+18=2x+12
-2x=-2x
2x+18=12
-18=-18
2x=-6
2x/2=-6/2
x=-3

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Answer:

The remainder is zero

Step-by-step explanation:

To find the remainder we will use the long division

$\frac{x^{3}-6x^{2}-5x-14}{x-7}=x^{2}\frac{x^{2}-5x-14 }{x-7}$ ⇒(1)

$\frac{x^{2}-5x-14}{x-7}=x\frac{2x-14}{x-7}$ ⇒(2)

$\frac{2x-14}{x-7}=2$ ⇒(3)

From (1) , (2) and (3)

The quotient of the long division is $x^{2}+x+2$ and no remainder

So the remainder is zero

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