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aleksley [76]
3 years ago
14

It take Anna 45 minutes to walk 2 1/2 miles to the park. At this rate, how many minutes should it take her to walk 3 miles?

Mathematics
1 answer:
san4es73 [151]3 years ago
3 0
Anna walks 1 mile in 18 minutes. 18 x 2.5 = 45. if she walks 3 miles instead of 2.5, your only adding half of 18. so 45 + 9. Anna will walk 3 miles in 54 minutes. Hope that helped!
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5. What is the<br> complement of the<br> supplement of a 110° <br> angle?
Slav-nsk [51]
<h2>Answer:   20°</h2>

<h3>Step-by-step explanation:</h3>

Supplementary angles sum up to 180 °

Complementary angles sum up to 90°.

The supplement of 110° = 180° - 110° = 70°

The complement of 70° = 90° - 70° = 20°

<u>Simplier version:</u>

The complement of the supplement of 110° = (90° - (180° - 110°))

                                                                         = 20°

3 0
2 years ago
Please help me
Solnce55 [7]

Answer:

4x^2-81y^2 is NOT a perfect square trinomial, factored. You know this because if you factor this to (2x+9y)(2x-9y) then you will see that the signs between terms in the parenthesis are DIFFERENT.

Step-by-step explanation:

Taking notes as you go through the course will help you retain and process the information much better than getting "help" from a site that is probably badly named.

4 0
3 years ago
Denise and Jacqueline are training for a swimming and running race.
bezimeni [28]

Answer:

Jacqueline runs at 6.25 minutes per mile

Step-by-step explanation:

Here we have that the total training time for Jacqueline = 54 minutes

The time for which Jacqueline swims = 30 minutes

Therefore, the time in which Jacqueline runs = 54 min. - 30 min. = 20 minutes

Therefore the equation for Jacqueline's speed = Distance/Time we have

Jacqueline's pace = 3.2 miles/20 minutes = 0.16 miles/minute

Therefore Jacqueline's pace = 0.16 miles/minute

The equation for Jacqueline's pace in miles/minute is presented as follows

Jacqueline's pace in miles/minute = Time of running/Distance

Jacqueline's pace in miles/minute  = 1/0.16 miles/minute = 6.25 minutes/mile.

5 0
3 years ago
Please help cause I don’t know how to do this
zalisa [80]

Answer:

  4 GB

Step-by-step explanation:

Let "g" represent the number of gigabytes of data used. Then the phone bill is computed as ...

  bill = 65 + 12g

Aurora's bill is 113, so we can put that value into the equation and solve for g.

  113 = 65 + 12g

  48 = 12g . . . . . . subtract 65 from both sides of the equation

  4 = g . . . . . . . . . divide both sides of the equation by 12

Aurora used 4 gigabytes of data in September.

_____

You can also use your mathematical reasoning to solve this problem. The total bill consists of two charges: a fixed charge of 65 and a charge that depends on data. If you subtract the fixed charge from the bill, you find that the charge that depends on data is 113-65 = 48.

The data charge is 12 times the number of gigabytes. The data charge on the bill is 48, which is 12 times 4. Then the number of gigabytes is 4.

7 0
3 years ago
What is the constant of variation for this relationship?
____ [38]
The constant is -12. I think of constant as the "lonely little number".... Hope this helped =)
4 0
3 years ago
Read 2 more answers
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