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4vir4ik [10]
1 year ago
12

A cyclist rides at a constant speed of 15 miles per hour. At this speed, about how long would it take the cyclist to ride from G

arden City to Dodge City, Kansas?
Mathematics
1 answer:
goblinko [34]1 year ago
3 0

Answer: 5.61333333 h

If the length between Garden city to dodge city is 84.2km the answer would be 5.61333333 hours [non-terminating decimal]

Step-by-step explanation:

So ummm, i dunno if the answer is right but yeahh

1h = 15 miles

Distance between GC AND DC = 84.2

84.2 * 15 = 5.6133333

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sergiy2304 [10]
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Which of the following is not a function?
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6 0
3 years ago
-11.2+4(2.1+q) = -0.8<br>solve and can you explain how to solve? I am confused 
Gekata [30.6K]
Given
-11.2+4(2.1+q) = -0.8

Take -11.2 to the right hand side of the equation (sign will change when we move it to the other side)
∴ 4(2.1+q) = -0.8 + 11.2

Simply both sides
∴ 4*2.1 + 4*q = 11.2-0.8
∴ 8.4 + 4q = 10.4

Take 8.4 to the right hand side
∴ 4q = 10.4 - 8.4
∴ 4q = 2
∴ q = 2/4
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6 0
4 years ago
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8 0
3 years ago
A culture started with 5000 bacteria after three hours it grew 6500 bacteria predict how many bacteria will be present after 13
charle [14.2K]

Answer:

15595 bacteria will be present after 13 hours.

Step-by-step explanation:

Continuous population growth:

The continuous population growth model, for the population after t hours, is given by:

P(t) = P(0)e^{rt}

In which P(0) is the initial population and r is the growth rate.

Started with 5000 bacteria

This means that P(0) = 5000

So

P(t) = 5000e^{rt}

After three hours it grew 6500 bacteria:

This means that P(3) = 6500. We use this to find r.

P(t) = 5000e^{rt}

6500 = 5000e^{3r}

e^{3r} = \frac{65}{50}

\ln{e^{3r}} = \ln{\frac{65}{50}}

3r = \ln{\frac{65}{50}}

r = \frac{\ln{\frac{65}{50}}}{3}

r = 0.0875

So

P(t) = 5000e^{0.0875t}

How many bacteria will be present after 13 hours?

This is P(13). So

P(13) = 5000e^{0.0875*13} = 15594.8

Rounding to the nearest whole number

15595 bacteria will be present after 13 hours.

7 0
3 years ago
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