Answer:
The escape speed for the craft is 1.49 m/s.
Explanation:
In this case we need to find the escape speed for a craft launched from a space elevator at a height of 56,000 km. The escape velocity is given by :
Here,
G is universal gravitational constant
M is mass of earth
d = r + h, r is radius of Earth
So, the escape speed for the craft is 1.49 m/s.
Ohm's law states that,
V = I x R
where V, I, and R are voltage, current, and resistance, respectively. Rearranging the equation gives,
R = V / I
Replacing the variables with the given values,
R = 1.5 volts / 2.0 amp
The answer is letter B. 0.75 ohms.
Sound waves<span> are longitudinal </span>waves<span>: the air moves back and forth along the same line as the </span>wave<span> travels, making alternate patterns of compressions and rarefactions. Bottom: Ocean </span>waves<span> are transverse </span>waves<span>: the water moves back and forth at right angles to the line in which the </span>wave travels<span>.</span>
Law of conservation of momentum
67*x=4.2*5.6
