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3 years ago

Which requires more work, lifting a 10.0kg load a vertical distance of 2m or lifting a 5.0kg load a distance of 4m?

1 answer:

6 0

For each load, Work = (mass) x (gravity) x (distance .

Bigger load: Work = (10 kg) x (9.8 m/s²) x (2 m) = 196 joules .

Smaller load: Work = (5 kg) x (9.8 m/s²) x (4 m) = 196 joules.

The work required is equal in both cases.

The mass ratio of 2:1 is exactly balanced by
the height ratio of 1:2 .

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To make a given sound seem twice as loud, how should a musician change the intensity of the sound?

Serhud [2]

Answer:

C. Quadruple the intensity

Explanation:

The intensity of the sound is proportional to square of amplitude of the sound.

I ∝ A²

$\frac{I_1}{A_1^2} = \frac{I_2}{A_2^2}\\\\I_2 = \frac{I_1A_2^2}{A_1^2}$

When the given sound is twice loud as the initial value, then the new amplitude is twice the former.

A₂ = 2A₁

$I_2 = \frac{I_1A_2^2}{A_1^2} \\\\I_2 = \frac{I_1(2A_1)^2}{A_1^2} \\\\I_2 = \frac{4I_1A_1^2}{A_1^2}\\\\ I_2 = 4I_1$

Thus, to make a given sound seem twice as loud, the musician should Quadruple the intensity

3 0

3 years ago

define the term change and state one negative change you may encounter as a student or as an employee in the future

Brums [2.3K]

Answer:

hey iam bored pls join

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Password: 1111

6 0

3 years ago

Starting from rest, a particle that is confined to move along a straight line is accelerated at a rate of 5.0 m/s2. Which one of

Elanso [62]

Answer:

c) The slope is not constant and increases with increasing time.

Explanation:

The equation for the position of this particle (starting from rest is)

$s = at^2/2 = 5t^2/2 = 2.5t^2$

We can take derivative of this with respect to time t to get the equation of slope:

$s' = (2.5t^2)' = 2*2.5t = 5t$

As time t increase, the slope would increases with time as well.

6 0

3 years ago

A wheelbarrow is a complex machine that combines which simply marchines?

koban [17]

It's most likely the combination of a bucket and the wheel.

4 0

3 years ago

Read 2 more answers

Suppose our apparatus will only allow us to distinguish the first order bright fringe from the central bright spot if they are s

ozzi

Answer:

λ = 8.716 mm

Explanation:

Given:

- d = 10 cm

- Q >= 5 degrees

Find:

- Find the shortest wavelength of light for which this apparatus is useful

Solution:

- The formula that relates the split difference and angle of separation between successive fringes is given by:

d*sin(Q) = n*λ

Where,

λ: wavelength

d: split separation

Q: angle of separation between successive fringes

m: order number.

- Since this apparatus only shows the first order light so m =1

- the shortest possible wavelength corresponds to:

d*sin(Q) = λ

λ = 0.1*sin(5)

λ = 8.716 mm

3 0

3 years ago