These are two questions and two answers.
Part 1. Fin the value of the ration of velocity C to velocity D.
Answer: 2
Explanation:
1) Formula: momentum = mass * velocity
2) momentum C = mass C * velocity C
3) momentum D = mass D * velocity D.
4) C and D have the same momentum =>
mass C * velocity C = mass D * velocity D
5) mass C = (1/2) mass D => mass C / mass C = 1/2
6) use in the equation stated in the point 4)
velocit C / velocity D = mass D / mass C
using the equation stated in point 5:
mass D / mass C = 1 / [ mass C / mass D] = 1 / [1/2] = 2
=>
7) velocity C / velocity D = mass D / mass C = 2
Part 2: <span>ratio of kinetic energy C to kinetic energy D.
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Answer: 2
Explanation:
1) formula: kinetic energy KE = (1/2) mass * (velocity)^2
2) KE C = (1/2) mass C * (velocity C)^2
3) KE D = (1/2) mass D * (velocity D)^2
4) KE C / KE D =
(1/2) mass C * (velocity C)^2 mass C (velocity C)^2
--------------------------------------- = --------------- * ---------------------- = (1/2) * (2)^2
(1/2) mass D *( velocity D)^2 mass D v(velocity D)^2
= 4 / 2 = 2
Answer:
630.75 j
Explanation:
from the question we have the following
total mass (m) = 54.5 kg
initial speed (Vi) = 1.4 m/s
final speed (Vf) = 6.6 m/s
frictional force (FF) = 41 N
height of slope (h) = 2.1 m
length of slope (d) = 12.4 m
acceleration due to gravity (g) = 9.8 m/s^2
work done (wd) = ?
- we can calculate the work done by the boy in pushing the chair using the law of law of conservation of energy
wd + mgh = (0.5 mVf^2) - (0.5 mVi^2) + (FF x d)
wd = (0.5 mVf^2) - (0.5 mVi^2) + (FF x d) - (mgh)
where wd = work done
m = mass
h = height
g = acceleration due to gravity
FF = frictional force
d = distance
Vf and Vi = final and initial velocity
wd = (0.5 x 54.5 x 6.9^2) - (0.5 x 54.5 x 1.4^2) + (41 x 12.4) - (54.5 X 9.8 X 2.1)
wd = 630.75 j
A quadrilateral with only one pair of parallel sides.
<span>a small carpal bone in the base of the hand, articulating with the metacarpal of the index finger.
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