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3 years ago

Which kind of waves are sound vibrations made of? transverse circular longitudinal latitudinal

2 answers:

8 0

Sound waves are longitudinal waves: the air moves back and forth along the same line as the wave travels, making alternate patterns of compressions and rarefactions. Bottom: Ocean waves are transverse waves: the water moves back and forth at right angles to the line in which the wave travels.

jasenka [17]3 years ago

4 0

which kind of waves are sound vibrations made of?

longitudinal

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3. A block with a force of the Earth of -300. N is moved at constant velocity over a horizontal surface by a force of +50.0 N ap

KIM [24]

Answer:

-6

Explanation:

FRICTIONAL force=-300N,NORMAL REACTION,R=+50.0

Ú=F/R

=-300/+50.0

=-6

3 0

3 years ago

One hundred turns of (insulated) copper wire are wrapped around a wooden cylindrical core of cross-sectional area 1.32 × 10-3 m2

kenny6666 [7]

Answer:

The charge flos through the coil is 0.023C

Explanation:

To solve this problem, it is necessary to apply the concepts related to Faraday's Law in which it is possible to calculate the emf Voltage induced due to a charge in a magnetic field

and Ohm's Law for the calculation of the current based on a given load over time.

Our data are given by:

$N=100$

$A= 1.32*10^{-3}m^2$

$R=15\Omega$

Where

N is the number of loops, A the area and R the Resistance.

The change in magnetic field can be calculated as,

$dB = 1.31-(-1.31)$

$dB = 2.62T$

The Faraday's law of electromagnetic induction is given by definition as,

$V = NA \frac{dB}{dt}$

In the other hand Ohm's law says:

$V = IR$

$V = \frac{dq}{dt} R$

Equating both equations we have

$\frac{dq}{dt} R = NA \frac{dB}{dt}$

We can re-arrange the equations to solve q, then

$dq = \frac{NA(dB)}{R}$

$q = \frac{(100)(1.32*10^{-3})(2.62)}{15}$

$q = 0.023C$

Therefore the charge flos through the coil is 0.023C

8 0

3 years ago

A car with a speed of 50ms is stopped when its brakes are pressed. The displacement passed before stopping is 150 m. How much de

monitta

I dont think it can be solved as time is not mentioned

8 0

3 years ago

Water flows past a flat plate that is oriented parallel to the flow with an upstream velocity of 0.4 m/s. (a) Determine the appr

Trava [24]

Answer:

1.12 m

0.08291 m

Explanation:

u = Upstream velocity = 0.4 m/s

Re = Reynold's number = $5\times 10^5$ (turbulent)

$\nu$ = Viscosity of water = $1.12\times 10^{-6}\ Pas$

Here the flow is turbulent so we have the relation

$Re_{xcr}=\frac{ux_{cr}}{\nu}\\\Rightarrow x_{cr}=\frac{Re_{xcr}\nu}{u}\\\Rightarrow x_{cr}=\frac{5\times 10^5\times 1.12\times 10^{-6}}{0.4}\\\Rightarrow x_{cr}=1.4\ m$

The approximate location downstream from the leading edge where the boundary layer becomes turbulent is 1.4 m

Boundary layer thickness relation is given by

$\delta={\frac{\nu x}{u}}^{\frac{1}{5}}\\\Rightarrow \delta={\frac{1.12\times 10^{-6}\times 1.4}{0.4}}^{\frac{1}{5}}\\\Rightarrow \delta=0.08291\ m$

The boundary layer thickness is 0.08291 m

4 0

4 years ago

A 12 kg box is pulled across the floor with a 48 N horizontal force. If the force of friction is 12 N, what is the acceleration

Oksi-84 [34.3K]

Answer:

The acceleration of the box is 3 m/s²

Explanation:

Given;

mass of the box, m = 12 kg

horizontal force pulling the box forward, Fx = 48 N

frictional force acting against the box in opposite direction, Fk = 12 N

The net horizontal force on the box, F = 48 N - 12 N

The net horizontal force on the box, F = 36 N

Apply Newton's second law of motion to determine the acceleration of the box;

F = ma

where;

F is the net horizontal force on the box

a is the acceleration of the box

a = F / m

a = 36 / 12

a = 3 m/s²

Therefore, the acceleration of the box is 3 m/s²

7 0

3 years ago