Answer:
1.0416 m∧3/sec
Explanation:
check the pictures below for the solution
The paper dielectric in a paper-and-foil capacitor is 0.0800 mm thick. Its dielectric constant is 2.50, and its dielectric stren
1 answer:
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Answer:
1. The final velocity of the penny before it hits the ground is approximately 54.25 m/s
2. The velocity after falling 45 meters is approximately 37.10 m/s
3. The height up the hill one can start without going over the smaller hill is approximately 2.75 meters
Explanation:
The height of the Bellagio, h = 150 meters
The mass of the penny, m = 1 kg
The kinematic equation of motion that can be used to find the final velocity of the penny 'v' before it hits the ground, is presented as follows;
v² = u² + 2·g·h
Where;
v = The final velocity of the penny after dropping through a height, 'h'
u = The initial velocity of the penny = 0 m/s for the penny initially at rest
g = The acceleration due to gravity ≈ 9.81 m/s²
h = The height from which the penny was dropped = 150 m
∴ v² ≈ 0² + 2 × 9.81 × 150 = 2,943
v ≈ √2,943 ≈ 54.25
The final velocity of the penny before it hits the ground, v ≈ 54.25 m/s
2. Here, the initial velocity, u = 80 km/h = 80 km/h × 1000 m/km × 1 h/(60 × 60 s) = 200/9 m/s = 22. m/s
The height of supreme scream, = 90 meters
The height at which the velocity is required, h = 45 meters
From v² = u² + 2·g·h, we get;
v² = 22.² + 2 × 9.81 × 45 ≈ 1,376.73
∴ v = √1,376.73 ≈ 37.10
The velocity 'v' after falling 45 meters is, v = 37.10 m/s
3. The height of the smaller hill, h = 5 meters
The running start = 4 m/s = The initial velocity
The velocity required to reach the height, h, of the smaller heal v = √(2·g·h)
∴ v = √(2 × 9.81 m/s² × 5 m) ≈ 9.9 m/s
The height 'h'' up the larger hill that will give a velocity, 'v', at the bottom of the smaller hill of approximately 9.9 m/s with an initial velocity, u = 4 m/s, is given as follows;
v² = u² + 2·g·h'
9.9² = 4² + 2 × 9.81 × h'
∴ h' = 9.9²/(4² + 2 × 9.81) ≈ 2.75
Given that the running start is 40 m/s, the height up the hill one can start without going over the smaller hill, h' ≈ 2.75 meters
The amount of heat required for the sublimation of 40.0 g of solid dry ice CO₂ is <u>29.3 kJ.</u>
One mole of CO₂ has a mass of 44.0095 g.
Calculate the number of moles n in 40.0 g of CO₂ .
Heat of sublimation is the amount of heat required by 1 mole of a substance to convert itself from solid state to a vapor state at constant temperature and pressure.
1 mole of CO₂ requires 32.3 kJ of energy to sublimate.
Therefore, the heat required to sublimate 0.9089 mol of CO₂ is given by,
Thus, the heat required to sublimate 40.0 g of CO₂ is <u>29.3 kJ</u>.