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xz_007 [3.2K]
3 years ago
7

Triangle ABC is an obtuse triangle with the obtuse angle at vertex B. Angle A must be

Mathematics
2 answers:
vagabundo [1.1K]3 years ago
5 0
The correct answer is less than 90°
Temka [501]3 years ago
3 0

Answer:

less than 90°.

Step-by-step explanation:

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What is the area of the parllelogtam shown below
Umnica [9.8K]
<h3>Answer: 16 square units</h3>

Let x be the height of the parallelogram. Right now it's unknown, but we can solve for it using the pythagorean theorem. Focus on the right triangle. It has legs a = 3 and b = x, with hypotenuse c = 5

a^2 + b^2 = c^2

3^2 + x^2 = 5^2

9 + x^2 = 25

x^2 = 25-9

x^2 = 16

x = sqrt(16)

x = 4

This is a 3-4-5 right triangle.

The height of the parallelogram is 4 units.

We have enough info to find the area of the parallelogram

Area of parallelogram = base*height

Area of parallelogram = 4*4

Area of parallelogram = 16 square units

Coincidentally, the base and height are the same, which isn't always going to be the case. The base is visually shown as the '4' in the diagram. The height is the dashed line, which also happens to be 4 units long.

6 0
3 years ago
If carbon monoxide reaches a temperature of over 1,100 degrees Fahrenheit, it will ignite in a combustion reaction with oxygen.
fiasKO [112]

Answer:

A. 2CO + O2 ---> 2CO2

Step-by-step explanation:

2CO + O2 ---> 2CO2

6 0
3 years ago
Read 2 more answers
-4x+3y=-27<br> get y by its self
padilas [110]
3y=4x-27
y=4/3x-9
That’s how you do the equation
3 0
3 years ago
(29) A runner is running 10 miles per hour.
leva [86]

The conversions factors needed are 1 mile= 5280 feet and 1 hour = 3600 seconds, speed in ft/s = 14.67 ft/s  

<u>Solution: </u>

Given, A runner is running 10 miles per hour.  

We have to find what conversion factors should be used to convert 10 mi/hr to ft/s?

Now, speed of runner = 10 miles per hour.

But we need the units to be in ft / s.

Then, conversion factors are miles to feet and hours to seconds.

Now, miles to feet ⇒ 1 mile = 5280 feet.

Now, hours to seconds ⇒ 1 hour = 3600 seconds

\begin{array}{l}{\text { So,speed }=10 \frac{\text { miles }}{\text { hour }}} \\\\ {\text { speed }=10 \times \frac{1 \text { miles }}{1 \text { hour }}} \\\\ {\text { Speed }=10 \times \frac{5280 \text { feet }}{3600 \text { seconds }}} \\\\ {\text { Speed }=\frac{52800}{3600}=14.67 \mathrm{ft} / \mathrm{s}}\end{array}

Hence, the conversions needed are 1 mile = 5280 feet and 1 hour = 3600 seconds, speed in ft/s = 14.67 ft/s

6 0
3 years ago
What is the quotient of 7^2/2x+6 divided by 3x-5/x+3
Reil [10]

\bf \cfrac{7^2}{2x+6}\div \cfrac{3x-5}{x+3}\implies \cfrac{7^2}{2x+6}\cdot \cfrac{x+3}{3x-5}\implies \cfrac{49}{2~~\begin{matrix} (x+3) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}\cdot \cfrac{\begin{matrix} x+3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} }{3x-5}\implies \cfrac{49}{2(3x-5)}

6 0
3 years ago
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