Question

A scuba diver has a taut rope connecting the dive boat to an anchor on the ocean floor. The rope is 90 feet long and the water is 80 feet deep. To the nearest tenth of a foot, how far is the anchor from a point directly below the boat?

Answer 1

Answer:

41.2 feet

Step-by-step explanation:

Refer the attached figure .

A scuba diver has a taut rope connecting the dive boat to an anchor on the ocean floor. The rope is 90 feet i.e. AC = 90 feet.

The depth of water i.e. AB  = 80 feet.

We are supposed to find how far is the anchor from a point directly below the boat i.e. BC

So, to find BC we will use Pythagoras theorem :

$Perpendicular^2+Base^2=Hypotenuse^2$

$AB^2+BC^2=AC^2$

$80^2+BC^2=90^2$

$6400+BC^2=8100$

$BC^2=8100-6400$

$BC^2=1700$

$BC=\sqrt{1700}$

$BC=41.2 feet$

Thus the anchor is 41.2 feet from a point directly below the boat.

Answer 2

 41.2 ft is the answer to your question hope this helps.