Answer:
4r² - 5r - 15 / r(r+3)
Step-by-step explanation:
To solve this problem, we will proceed the following way, writing down the common multiple of the denominators.
Thus, the answer is 4r² - 5r - 15 / r(r+3)
Suppose $a$ and $b$ are the solutions to the quadratic equation $2x^2-3x-6=0$. Find the value of $(a+2)(b+2)$.
1 answer:
You might be interested in
Answer:
x = 12
Step-by-step explanation:
The segment from the vertex to the base is a perpendicular bisector.
Using Pythagoras' identity on the right triangle on the right.
( x )² + 3² = (
)² , that is
x² + 9 = 45 ( subtract 9 from both sides )
x² = 36 ( multiply both sides by 4 )
x² = 144 ( take the square root of both sides )
x = = 12
Answer:
Step-by-step explanation:
find the composition of g(x)=x−1 and h(x)=
hence we will get,
(g∘h)(x)=g(h(x))= g(x−1)= f(√x)= -1+√x = √x -1
Now to find f(g(h(x))),
f(x)=x4+6 and g(h(x))=√x -1
hence , putt g(h(x)) in f(x) ,
f(g(h(x)))=+6 -
Plzzzz Brain-list it or subscribe to my channel " ZK SOFT&GAMING"