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Furkat [3]
3 years ago
6

Suppose $a$ and $b$ are the solutions to the quadratic equation $2x^2-3x-6=0$. Find the value of $(a+2)(b+2)$.

Mathematics
1 answer:
Charra [1.4K]3 years ago
4 0
We have that

2x²<span>-3x-6=0
using a graph tool----------> to resolve the second order equation
see the attached figure
the solution is 
x=-1.137
x=2.637

therefore
a=-1.137
b=2.637
so
</span>(a+2)*(b+2)-----------> (-1.137+2)*(2.637+2)--------> 0.863*4.637---> 4

the answer is 4

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Given f(x)=3x-1 find f(-1)
vaieri [72.5K]

Answer:

<h2>f( - 1) = - 4</h2>

Step-by-step explanation:

f(x) = 3x - 1

To find f(-1) substitute the value of x that's

- 1 into f(x). That's for every x in f(x) replace it with - 1 and solve

That's

f( - 1) = 3(-1) - 1

= - 3 - 1

We have the final answer as

<h3>f(-1) = - 4</h3>

Hope this helps you

7 0
3 years ago
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cricket20 [7]

Answer:39

Step-by-step explanation:

7 0
3 years ago
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7 0
3 years ago
What is the slope of the linear function above? Write any fractions as improper fractions, using a '/'. (PLEASE HELP ME)
aliina [53]
-3/2
Down 3
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8 0
2 years ago
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Guys I need the answers to number 16
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Graph it.  (Hint:  The graph is a straight dashed line, and you must shade one side of it, but not the other side.
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