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horrorfan [7]
3 years ago
11

Factor. x2−6x+8 Enter your answer in the boxes.

Mathematics
2 answers:
LUCKY_DIMON [66]3 years ago
7 0
<u><em>Answer:</em></u>
The factored form is: (x-2)(x-4) = 0

<u><em>Explanation:</em></u>
To factor an expression, we need to <u>get its solutions</u>.

<u>The standard form of the quadratic equation is:</u>
ax² + bx + c = 0

<u>The given equation is:</u>
x² - 6x + 8 = 0

<u>By comparison:</u>
a = 1
b = -6
c = 8

Now, to get the roots, we will substitute with the values of a, b and c in the quadratic formula shown in the attached image.

<u>This will give us:</u>
either x = \frac{6+ \sqrt{(-6)^2-4(1)(8)} }{2(1)} = 4
This means that the first factor is (x-4)

or x = \frac{6- \sqrt{(-6)^2-4(1)(8)} }{2(1)} = 2
This means that the second factor is (x-2)

Based on the above, the factored form would be:
(x-4)(x-2) = 0

Hope this helps :)

avanturin [10]3 years ago
5 0

Answer:

(x-2)(x-4)

Step-by-step explanation:

x^2 -6x +8

We need to find numbers that add to -6 but multiply  8. We know that 4 and 2 multiply to 8 but they do not add to -6. -4 and -2 add to -6 and -4 times -2 equal 8. Therefore the factored form of x^2 -6x + 8 is (x-2)(x-4).

Hope this helps:))) Hva e a good day

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