Us tradional 289 *13

Given the following triangle solve for the unknown angle.

svetlana [45]

Since it is shown that 2 of the sides of the triangle are congruent, we can assume that they have the same angle measures.

so to solve for the missing angle you can set up an equation equal to 180 since all triangles add up to 180 degrees.
21 + 21 + x = 180
42 + x = 180
x = 138

the value of the missing angle should be 138 degrees

hope this helped

4 0

3 years ago

The quadratic function h(t) = -16.1? + 150 models a ball's height, in feet, over time, in seconds,

Sliva [168]

<h2>Hello!</h2>

The answer is: The first graphic representation.

We are given a quadratic equation, meaning that it could be two possible solutions for the exercise, however, we are talking about time, so we have to consider only the obtained positive values.

Let's make the equation equal to 0 in order to find the values of "t"

$h(t) = -16.1t^2 + 150$

$0=-16.1t^2+150$

$16.1t^2=150$

$t^2=\frac{150}{16.1} =9.32$

$t=+-\sqrt{9.32} =+-3.05$

$t1=3.05$

$t2=-305$

So, discarding the negative value, we can use the possitive value to find the correct graphic representation.

To find the correct graphic representation we must take into consideration the following:

- We must remember that the sign of the coefficient of the quadratic term (t^2) will define if the parabola opens downward or upward.

From the given quadratic (or parabola) equation we have:

$a=-1$

$b=0$

$c=150$

So, since the coefficient of the quadratic term is negative, the parabola opens downward.

- Since we are looking for a graphic that represents the change in height over time, we need to look for a graphic that shows only positive values for the x-axis (time)

- We are looking for a parabola which y-axis intercept is equal to 150.

Therefore, the graphic representation of the quadratic function that models a ball's height over time is the first graphic representation.

Have a nice day!

5 0

1 year ago

1 lb 0.454 kg About how many kilograms are in 21 pounds?

Semmy [17]

Answer:

21 Pounds =

9.5254398 Kilograms

(rounded to 8 digits)

Step-by-step explanation:

<em>Pounds : The pound or pound-mass (abbreviations: lb, lbm, lbm, ℔[1]) is a unit of mass with several definitions. Nowadays, the most common is the international avoirdupois pound which is legally defined as exactly 0.45359237 kilograms. A pound is equal to 16 ounces. </em>
<em>Kilograms : The kilogram (or kilogramme, SI symbol: kg), also known as the kilo, is the fundamental unit of mass in the International System of Units. Defined as being equal to the mass of the International Prototype Kilogram (IPK), that is almost exactly equal to the mass of one liter of water. The kilogram is the only SI base unit using an SI prefix ("kilo", symbol "k") as part of its name. The stability of kilogram is really important, for four of the seven fundamental units in the SI system are defined relative to it.</em>

3 0

1 year ago

Without graphing, determine whether the following pair of lines are parallel, perpendicular, or neither parallel nor perpendicul

Tomtit [17]

Write the equation of the lines in slope-intercept form (y=mx+b)

First equation: It is already in slope-intercept form

$y=\frac{2}{5}x-4$

Second equation: solve y:

$\begin{gathered} 4x-10y=-7 \\ 4x-4x-10y=-4x-7 \\ -10y=-4x-7 \\ \frac{-10}{-10}y=\frac{-4}{-10}x-\frac{7}{-10} \\ \\ y=\frac{4}{10}x+\frac{7}{10} \\ \\ y=\frac{2}{5}x+\frac{7}{10} \end{gathered}$

Identify the slope of each line:

If two or more lines have the same slope then the lines are parallel

If two lines have slopes that are negative reciprocals then the lines are perpendicular

The two given lines have the same slope: 2/5. Then, they are parallel lines

4 0

2 months ago

Why did the architects design Savannah on a grid system?

Gwar [14]

<span>To create a flexible street/block pattern that would accommodate a range of densities and residential and recreational uses, the Canadian planners adapted the street grid of Savannah to allow development of individual but continuous neighborhoods.</span><span>

The original </span>plan actually called for six squares, and as the city grew the grid<span> of wards and squares was extended so that 33 square.

</span>

8 0

2 years ago