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Lena [83]
3 years ago
6

In Rutherford's experiment, which of the following proved that the

Physics
1 answer:
vampirchik [111]3 years ago
5 0

Answer:

b) the alpha particles were found to be attracted to the nucleus

Explanation:

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A person jogs eight complete laps around a quarter-mile track in a total time of 12.5 min. Calculate (a) the average speed and (
Margarita [4]

\large\displaystyle\text{$\begin{gathered}\sf \huge \bf{\underline{Data:}} \end{gathered}$}

  • \large\displaystyle\text{$\begin{gathered}\sf 1\ mile = 1609.34 \ m \end{gathered}$}
  • \large\displaystyle\text{$\begin{gathered}\sf  1/4 \ mile = 402.33 \ m \end{gathered}$}

                           \large\displaystyle\text{$\begin{gathered}\sf 12.5 \not{min}*\frac{60 \ s}{1\not{min}}=750 \ s \end{gathered}$}

                   \large\displaystyle\text{$\begin{gathered}\sf \bf{A) \ Calculate \ the \ average \ speed: } \end{gathered}$}

                         \large\displaystyle\text{$\begin{gathered}\sf 402.33 \ m*8 \ laps = 3218.64 \ m \end{gathered}$}

                         \large\displaystyle\text{$\begin{gathered}\sf d=3218.64 \ m \end{gathered}$}

                         \large\displaystyle\text{$\begin{gathered}\sf t=750 \ s \end{gathered}$}

                         \large\displaystyle\text{$\begin{gathered}\sf V=\frac{d}{t} \ \ \ \ \ \  V= \frac{3218.64 \ m }{750 \ s} \end{gathered}$}\\\\\\\large\displaystyle\text{$\begin{gathered}\sf V=4.29 \ m/s \end{gathered}$}

                  \large\displaystyle\text{$\begin{gathered}\sf \bf{B) \ Calculate \ the \ average \ speed \  in \ m/s} \end{gathered}$}

                          \large\displaystyle\text{$\begin{gathered}\sf V=402.33 \ m \end{gathered}$}  

                          \large\displaystyle\text{$\begin{gathered}\sf t=750 \ s \end{gathered}$}

                          \large\displaystyle\text{$\begin{gathered}\sf V=\frac{D}{T} \ \ \ \ \ V=\frac{402.33 \ m}{750 \ s}   \end{gathered}$}\\\\\\\large\displaystyle\text{$\begin{gathered}\sf V= 0.53 \ m/s \end{gathered}$}

4 0
2 years ago
Three students attempt to define what it means for lines lll and mmm to be perpendicular. Can you match the teacher's comments t
Ber [7]

Incompletevquestion. However, I inferred from a general perspective about perpendicular lines.

<u>Explanation:</u>

Put simply, <u>perpendicular lines</u> are lines that are at right angles (90°) to each other. Thus, we could say based on this definition that for lines lll and mmm to be perpendicular they intersect and be at right angles (90°) to each other as <u>found on the attached image.</u>

3 0
3 years ago
Carmen simplifies the expression (4y+8x+6)+25+(4x+6y+7). The coefficient of the variable y in her simplified answer is
PtichkaEL [24]
The answer of the problem is 12x+10y+38
8 0
3 years ago
Read 2 more answers
At constant pressure, a sample of a gas occupies 420 ml at 220 K. what volume does the gas occupy at 250 K?
soldier1979 [14.2K]

Answer:

480 mL

Explanation:

Ideal gas law states:

PV = nRT

At constant pressure, nR/P is constant.  Therefore:

V / T = V / T

420 mL / 220 K = V / 250 K

V ≈ 480 mL

5 0
3 years ago
An 835 kg dragster accelerates from rest to 110 km/h in 0.90 seconds.
sveticcg [70]

Answer

given,

mass of the dragster = 835 Kg

initial speed, u = 0 m/s

final speed, v = 110 km/h = 110 x 0.278 = 30.58 m/s

time, t = 0.90 s

a) Change in momentum

   Δ P = m v - m u

   Δ P = 835 x ( 30.58  - 0 )

   Δ P =  25534.3 kg.m/s

b) average force exerted on the car

    change in momentum = Force x time

            25534.3 = F x 0.9

              F = 28371.44 N

c) The exerted force is due to friction because the motion of the dragster is because of friction.

8 0
3 years ago
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