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liberstina [14]
2 years ago
5

A pump lifts 200 kg of water to a water tank placed at a height of 25m in 20 s. Find its power. g = 10 m/s² [Ans: 2500 W]​

Physics
1 answer:
sukhopar [10]2 years ago
4 0

Answer:

            2500W

Explanation:

                     P = W/t

             As we know that

                  W = mgh

             so:

                     P = mgh/t    

            put values

                      P = (200)(10)(25) / 20

                       <u><em>P = 2500W </em></u>

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An 80-kgkg quarterback jumps straight up in the air right before throwing a 0.43-kgkg football horizontally at 15 m/sm/s . How f
vladimir1956 [14]

Answer:

V = 0.0806 m/s

Explanation:

given data

mass quarterback = 80 kg

mass football = 0.43 kg

velocity = 15 m/s

solution

we consider here momentum conservation is in horizontal direction.

so that here no initial momentum of the quarterback

so that final momentum of the system will be 0

so we can say

M(quarterback) ×  V = m(football) × v (football)   ........................1

put here value we get

80 ×  V  = 0.43  × 15

V = 0.0806 m/s

5 0
3 years ago
Two states of matter are described below. State A: Cannot be compressed and retains its shape State B: Highly compressible Which
telo118 [61]

Answer:

State A = piece of metal; State B = air

Explanation:

For the three main states of matter here's how it breaks down.

Solid - Cannot be compressed and retains its shape

Liquid - Cannot be compressed and does not retain its shape

Gas - Compressible and does not retain its shape.

Knowing this State A has to be solid.  Only one of the options has A as a solid, so that's the answer.   Worth knowing state B is a gas though, only one compressible, just like solid is the only one that retains its shape.

7 0
4 years ago
Read 2 more answers
A -turn rectangular coil with length and width is in a region with its axis initially aligned to a horizontally directed uniform
madam [21]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The maximum emf is \epsilon_{max}= 26.8 V

The emf induced at t = 1.00 s is \epsilon = 24.1V

The maximum rate of change of magnetic flux is   \frac{d \o}{dt}|_{max}  =26.8V

Explanation:

    From the question we are told that

        The number of turns is N = 44 turns

          The length of the coil is  l = 15.0 cm = \frac{15}{100} = 0.15m

          The width of the coil is  w = 8.50 cm =\frac{8.50}{100} =0.085 m

          The magnetic field is  B = 745 \ mT

          The angular speed is w = 64.0 rad/s

Generally the induced emf is mathematically represented as

        \epsilon = \epsilon_{max} sin (wt)

 Where \epsilon_{max} is the maximum induced emf and this is mathematically represented as

            \epsilon_{max} = N\ B\ A\ w

Where \o is the magnetic flux

            N is the number of turns

             A is the area of the coil which is mathematically evaluated as

             A = l *w

        Substituting values

           A = 0.15 * 0.085

               = 0.01275m^2

substituting values into the equation for  maximum induced emf

         \epsilon_{max} = 44* 745 *10^{-3} * 0.01275 * 64.0

                 \epsilon_{max}= 26.8 V

 given that the time t = 1.0sec

substituting values into the equation for induced emf  \epsilon = \epsilon_{max} sin (wt)

      \epsilon = 26.8 sin (64 * 1)

        \epsilon = 24.1V

   The maximum induced emf can also be represented mathematically as

              \epsilon_{max} = \frac{d \o}{dt}|_{max}

  Where  \o is the magnetic flux and \frac{d \o}{dt}|_{max} is the maximum rate at which magnetic flux changes the value of the maximum rate of change of magnetic flux is

         \frac{d \o}{dt}|_{max}  =26.8V

8 0
3 years ago
Please Help Me
JulijaS [17]

1. a=Δv/Δt=(v-vo)/t=(0-25)/5=-25/5=-5 m/s²

The "-" sign shows us that the car has a slow motion


2.a=Δv/Δt=(v-vo)/t=(10-0)/4=10/4=2,5 m/s²


3.they do not have acceleration because they go at constant speed


7 0
4 years ago
The energy content of a certain food is to be determined in a bomb calorimeter that contains 3 kg of water by burning a 2-g samp
GuDViN [60]

Answer:

20.179 x 10⁶ J /kg

Explanation:

The food after the reaction gives out heat which increases the temperature of water and air in the reaction chamber . The heat absorbed by water and air gives the estimate of energy content of the food.

Heat absorbed by water = mass x specific heat x rise in temperature

=  3 x 4.18 x 10³ x 3.2

= 40.128 x 10³ J

Heat absorbed by air  = mass x specific heat x rise in temperature

0.1 x 3. 2 x .718 x 10³

= 0.23 x 10³

Total heat energy evolved

= 40.358 x 10³ J

This energy is evolved by 2 x 10⁻³ kg of food

energy content per kg of food

= 40.358 x 10³ / 2 x 10⁻³

= 20.179 x 10⁶ J /kg

7 0
3 years ago
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