All categories

2 years ago

A pump lifts 200 kg of water to a water tank placed at a height of 25m in 20 s. Find its power. g = 10 m/s² [Ans: 2500 W]

Physics

1 answer:

sukhopar [10]2 years ago

4 0

Answer:

2500W

Explanation:

P = W/t

As we know that

W = mgh

so:

P = mgh/t

put values

P = (200)(10)(25) / 20

P = 2500W

You might be interested in

1. Does a fish appear closer or farther from a person wearing swim goggles with an air pocket in front of their eyes than the fi

pychu [463]

Answer: I believe farther. Correct me if I am wrong

Explanation:

3 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP!!

Gwar [14]

The third one.

The nucleus of an atom is made up of protons and neutrons. Protons and neutrons have the same relative mass (rounded to 1). Electrons have an extremely small mass.

Therefore, the particles in the nucleus are more massive than those in the electron cloud.

4 0

2 years ago

Usually, when the temperture is increased l, what will happen to the ratevof dissolving?

pochemuha

When temperature is increased, the rate of dissolving increases. The kinetic energy of the molecules of the solute and solvent molecules is high thereby increasing their contact. An example is mixing powdered sugar to the water. When you add water to the sugar, the dissolving process is slow. However, when you increase the temperature of the water by boiling it, the sugar dissolves immediately.

3 0

3 years ago

A spherical balloon is made from a material whose mass is 3.00 kg. The thickness of the material is negligible compared to the 1

vesna_86 [32]

To solve the problem it is necessary to apply the definition of Newton's second Law and the definition of density.

Density means the relationship between volume and mass:

$\rho = \frac{m}{V}$

While Newton's second law expresses that force is given by

F = ma

Where,

m = mass

a= acceleration (gravity at this case)

In the case of the given data we have to,

$m_b = 3Kg$

$r = 1.5m\\V = \frac{4}{3}\pi r^3 \\V = \frac{4}{3} \pi 1.5^3\\V = 14.13m^3$

In equilibrium, the entire system is equal to zero, therefore

$\sum F = 0$

$F_g +F_h-F_b = 0$

Where,

$F_g =$ Weight of balloon

$F_h =$ Weight of helium gas

$F_b =$ Bouyant force

Then we have,

$mg+V\rho g -V\rho_a g = 0$

$\rho = \rho_0-\frac{m}{V}$

Replacing the values we have that

$\rho = 1.19kg/m^3 -\frac{3Kg}{14.13m^3}$

$\rho = 0.978kg/m^3$

Now by ideal gas law we have that

$PV=nRT$

$P\frac{\rho}{m} = nRT$

$P = \rho \frac{n}{m}RT$

But the relation \frac{n}{m} is equal to the inverse of molar mass, that is

$P = \frac{\rho}{M_0} RT$

$P = \frac{0.978kg/m^3}{0.04kg/mol}*8.314J/K.Mol * 305K$

$P = 619995.7Pa$

Therefore the pressure of the helium gas assuming it is ideal is 0.61Mpa

5 0

3 years ago

Find the magnitude of the emf induced in the rod when it is moving toward the right with a speed 7.50 m/s.

Flauer [41]

Answer:

3 volts

Explanation:

It is given that,

Magnetic field, B = 0.8 T

Length of a conducting rod, l = 50 cm = 0.5 m

Velocity of the conducting rod, v = 7.5 m/s

We need to find the magnitude of the emf induced in the rod when it is moving toward the right. When a rod is moved in a magnetic field, an emf is induced in it and it is given by :

$\epsilon=Blv$

Putting all the values,

$\epsilon=0.8\times 0.5\times 7.5\\\\\epsilon=3\ V$

So, the magnitude of the emf induced in the rod is 3 volts.

6 0

3 years ago

A pump lifts 200 kg of water to a water tank placed at a height of 25m in 20 s. Find its power. g = 10 m/s² [Ans: 2500 W]​

A pump lifts 200 kg of water to a water tank placed at a height of 25m in 20 s. Find its power. g = 10 m/s² [Ans: 2500 W]