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LenKa [72]
3 years ago
5

ASAP what is the equation x = y + z solved for z

Mathematics
2 answers:
AlexFokin [52]3 years ago
7 0
     x = y + z   Subtract y from both sides
x - y = z         Switch the sides to make it easier to read
     z = x - y
mixer [17]3 years ago
7 0
<span>x = y + z
Subtract y from both sides
Final Answer: x - y= z</span>
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First answer gets brainliest
strojnjashka [21]

Answer:

a=10% b= 25/100  c=1/2

Step-by-step explanation:

calculate

6 0
3 years ago
Read 2 more answers
The annual sales of romance novels follow the normal distribution. However, the mean and the standard deviation are unknown. For
Fynjy0 [20]

Answer:

Mean(m) = 462,536

sd = 29,268.29

Step-by-step explanation:

Given the following:

P(sales > 470,000) = 40% = 0.4

P(sales > 500,000) = 10% = 0.1

Using the z - table, we can locate the corresponding P values

Z = 1 - p = 1 - 0.4 = 0.6; 1 - 0.1 = 0.9

Locating the closest value to 0.6 on the z table ;

(0.25 + 0.26) / 2 = 0.255

Locating the closest value to 0.9 on the z table ;

Z = 1.28

Recall;

z =( x - m) / sd

Where m = mean ; sd = standard deviation

First condition:

0.255 = (470,000 - m) / sd

0.255 × sd = (470,000 - m) - - - - - (1)

1.28 = (500,000 - m) / sd

1.28 × sd = (500,000 - m) - - - - (2)

We can solve for one of the unknowns y subtracting equation (1) FROM 2

1.28sd - 0.255sd = (500,000 - m) - (470000 - m)

1.025sd =500,000 - m - 470000 + m

1.025sd = 30,000

sd = 29,268.29

Substituting the value od SD into (1) or (2)

1.28 × 29,268.29 = 500000 - m

37463.41 = 50000 - m

m = 50000 - 37463.41

Mean(m) = 462,536

7 0
3 years ago
21x^5y^4-18x^7y^3+15x^2y^5
soldi70 [24.7K]

Do you want us to answer or simplify?

Simplify:=−18x^7  y^3 + 21x^5  y^4+ 15x^2 y^5

5 0
3 years ago
Solve the following systems by substitution
Paladinen [302]

Answer:

The answer to your question is below

Step-by-step explanation:

Question 1

                x = 5                       Equation l

                2x + y = 10              Equation ll

- Substitute Equation l in equation ll

               2(5) + y = 10

                y = 10 - 10

                y = 0

- Solution  (5, 0)

Question 2

                 x + 16y = 20          Equation l

                 x = 4y                    Equation ll

Substitute equation ll in equation l

                4y + 16y = 20

                        20y = 20

                           y = 20/20

                           y = 1

-Find x

                x = 4(1)

                x = 4

-Solution

                (4, 1)

Question 3

                   2x + 8y = 20            Equation l

                     x = 2                       Equation ll

-Substitute equation ll in equation l

                   2(2) + 8y = 20

                      4 + 8y = 20

                            8y = 20 - 4

                            8y = 16

                              y = 16/8

                              y = 2

- Solution

                   (2, 2)              

8 0
3 years ago
Choose the product. -5p 3(4p 2 + 3p - 1) -20p 5 - 15p 4 + 5p 3 -20p 6 - 15p 4 - 5p 3 -20p 5 + 3p - 1 20p 5 + 15p 4 - 5p 3
Likurg_2 [28]
<span>-5p^3(4p^2 + 3p - 1) = -20p^5 - 15p^4 + 5p^3

answer is

A. first one
  </span>-20p^5 - 15p^4 + 5p^3
5 0
3 years ago
Read 2 more answers
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