Answer:
Hi how are you doing today Jasmine
Show the question so I can answer it for you.
Answer:
A. 4(x - 4) + 2(3x² + 3x - 20)
C. (11x² + 7x - 55)-(5x² - 3x + 1)
F. (3x² + 5x - 28) + (3x² + 5x - 28)
Step-by-step explanation:
Given:
(3x-7)(2x+8)
= 6x² + 24x - 14x - 56
=6x² + 10x - 56
A. 4(x - 4) + 2(3x² + 3x - 20)
= 4x - 16 + 6x² + 6x - 40
= 6x² + 10x - 56
B. (3x² + 5x - 28) - (2x² + 4x + 28)
= 3x² + 5x - 28 - 2x² - 4x - 28
= x² + x - 56
C. (11x² + 7x - 55)-(5x² - 3x + 1)
= 11x² + 7x - 55 - 5x² + 3x - 1
= 6x² + 10x - 56
D. 4(x - 4) - 2(3x² + 3x - 20)
= 4x - 16 - 6x² - 6x + 40
= - 6x² - 2x + 24
E. (11x² + 7x - 55)-(5x² - 3x + 2)
= 11x² + 7x - 55 - 5x² + 3x - 2
= 11x² - 5x² + 7x + 3x - 55 - 2
= 6x² + 10x - 57
F. (3x² + 5x - 28) + (3x² + 5x - 28)
= 3x² + 5x - 28 + 3x² + 5x - 28
= 6x² + 10x - 56
S = 4pi r^2
S/4pi = r^2
taking square root on both sides,
r = sqrt (S/4pi)
Answer:
The last choice is the correct one
Explanation:
We can solve this question using "difference between squares" which has the following general rule:
a^2 - b^2 = (a+b)(a-b)
For the given question:
p^4 - 16 = (p^2 - 4)(p^2 + 4)
Now, p^2 - 4 can be further factorized using difference between squares, therefore:
p^4 - 16 = (p-2)(p+2)(p^2 + 4)
Hope this helps :)
