What is the interquartile range of the data set below? Growth in feet of oak trees: 68,80,73,90,120,94,76,112,101,94,72 (1) 22
sdas [7]
<span>68,80,73,90,120,94,76,112,101,94,72 --->
68, 72, 73, 76, 80, 90, 94, 94, 101, 112, 120
Median = 90
Lower Median = 73
Upper Median = 101
IQR = 101 - 73
IQR = 28</span>
..................(1x+14y)4
Answer: 296 degrees
Step-by-step explanation:
Arc PRT is just the entire circumference - arc PT.
Since the 64 degree angle is a central angle, arc PT measures 64 degrees.
So arc PRT = 360 degree - 64 degree = 296 degrees.
