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goldfiish [28.3K]
2 years ago
6

Pls help will mark brainlis

Mathematics
1 answer:
MrRissso [65]2 years ago
3 0

Exponents  

5^2

4^2

8^2

7^2

3^2

9^2

12^2

Expound

5x5

4x4

8x8

7x7

3x3

9x9

12x12

Perfect square

25

16

64

49

9

81

36

144

Hope I helped you :)

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PLEASE HELP DONT JUST GUESS JUST TO GET POINTS LOL Plot any four points on the coordinate plane and connect them to form a quadr
sveticcg [70]

The quadrilateral formed by this process will always be a parallelogram

<h3>Quadrilaterals</h3>

A quadrilateral is simply any polygon that has four sides and four corners.

Common examples are:

  • Square
  • Rectangle
  • Rhombus
  • Kite
  • Trapezoid
  • Rhombus
  • Parallelogram

<h3>Figure 1</h3>

A square is drawn at the coordinates:

(0,0), (6,0), (0,6) and (6,6)

The midpoints of the square sides are at the following coordinates:

(0,3), (3,6), (6,3) and (3,0)

When the points of the midpoints are joined together, they form a parallelogram

<h3>Figure 2</h3>

A trapezoid is drawn at the coordinates:

(0,0), (2,6), (8,6) and (10,0)

The midpoints of the square sides are at the following coordinates:

(5,0), (5,6), (1,3) and (9,3)

When the points of the midpoints are joined together, they form a parallelogram

Hence, the quadrilateral formed by this process will always be a parallelogram

Read more about quadrilaterals and parallelograms at:

brainly.com/question/1190071

5 0
2 years ago
Distance between two ships At noon, ship A was 12 nautical miles due north of ship B. Ship A was sailing south at 12 knots (naut
frozen [14]

Answer:

a)\sqrt{144-288t+208t^2} b.) -12knots, 8 knots c) No e)4\sqrt{13}

Step-by-step explanation:

We know that the initial distance between ships A and B was 12 nautical miles. Ship A moves at 12 knots(nautical miles per hour) south. Ship B moves at 8 knots east.

a)

We know that at time t , the ship A has moved 12\dot t (n.m) and ship B has moved 8\dot t (n.m). We also know that the ship A moves closer to the line of the movement of B and that ship B moves further on its line.

Using Pythagorean theorem, we can write the distance s as:

\sqrt{(12-12\dot t)^2 + (8\dot t)^2}\\s=\sqrt{144-288t+144t^2+64t^2}\\s=\sqrt{144-288t+208t^2}

b)

We want to find \frac{ds}{dt} for t=0 and t=1

\sqrt{144-288t+208t^2}|\frac{d}{dt}\\\\\frac{ds}{dt}=\frac{1}{2\sqrt{144-288t+208t^2}}\dot (-288+416t)\\\\\frac{ds}{dt}=\frac{208t-144}{\sqrt{144-288t+208t^2}}\\\\\frac{ds}{dt}(0)=\frac{208\dot 0-144}{\sqrt{144-288\dot 0 + 209\dot 0^2}}=-12knots\\\\\frac{ds}{dt}(1)=\frac{208\dot 1-144}{\sqrt{144-288\dot 1 + 209\dot 1^2}}=8knots

c)

We know that the visibility was 5n.m. We want to see whether the distance s was under 5 miles at any point.

Ships have seen each other = s\leq 5\\\\\sqrt{144-288t+208t^2}\leq 5\\\\144-288t+208t^2\leq 25\\\\199-288t+208t^2\leq 0

Since function f(x)=199-288x+208x^2 is quadratic, concave up and has no real roots, we know that 199-288x+208x^2>0 for every t. So, the ships haven't seen each other.

d)

Attachedis the graph of s(red) and ds/dt(blue). We can see that our results from parts b and c were correct.

e)

Function ds/dt has a horizontal asympote in the first quadrant if

                                                \lim_{t \to \infty} \frac{ds}{dt}

So, lets check this limit:

\lim_{t \to \infty} \frac{ds}{dt}=\lim_{t \to \infty} \frac{208t-144}{\sqrt{144-288t+208t^2}}\\\\=\lim_{t \to \infty} \frac{208-\frac{144}{t}}{\sqrt{\frac{144}{t^2}-\frac{288}{t}+208}}\\\\=\frac{208-0}{\sqrt{0-0+208}}\\\\=\frac{208}{\sqrt{208}}\\\\=4\sqrt{13}

Notice that:

4\sqrt{13}=\sqrt{12^2+5^2}=√(speed of ship A² + speed of ship B²)

5 0
3 years ago
Please help, will give brainlist!
eimsori [14]

Answer:

The answer is B. (2.5,-0.5).

Step-by-step explanation:

You would substitute the ordered pair into the first equation, making it

3(2.5)-(-0.5)=8. So the equation would become 7.5-(-0.5)=8, or 7.5+0.5=8. 8=8 is a true statement.

3 0
3 years ago
1 m² · 100cm/1 m · 100cm/1 m =?
Y_Kistochka [10]
1 m² is the answer because 1<span>00cm/1 m equal to 1</span>
8 0
3 years ago
in Mr. whiteners class,7 out 35 students olay middle school basketball .what percent of studwnts in mr. Whitener's class play mi
MaRussiya [10]

Answer:

20%

Step-by-step explanation:

It would be 20% because 35/7 is 5 and 5 goes into 100% 20 times.

5 0
3 years ago
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