Answer:
8/15
Step-by-step explanation:
(2/5)/(3/4)=(2/5)(4/3)=8/15
Hey there,
Your question states: <span>A store charges $2.10 for a medium bag of fruit slices. Assuming that the rate stays the same, how much should the store charge for a large bag of the slices?
So sense this is a medium bad of fruit slices, we would divide 2.10 by 2.
Your answer would be 1.5 Now, all we do is we add 2.10+1.5 and we get 3.15. The reason would be because sense we now know the price of the size of it being small, we just add that size on top of the medium size to get 3.15.
Hope this helps.
~Jurgen</span>
It’s 4,2 the and the other on PQRS
Answer:
Step-by-step explanation:
first, we find the slope
slope = (y2 - y1) / (x2 - x1)
(8,2)....x1 = 8 and y1 = 2
(7,1)....x2 = 7 and y2 = 1
now we sub
slope = (1 - 2) / (7 - 8) = -1/-1 = 1
y = mx + b
slope(m) = 1
use either of ur points...I will use (8,2)...x = 8 and y = 2
now we sub and find b, the y intercept
2 = 1(8) + b
2 = 8 + b
2 - 8 = b
-6 = b
so ur equation is : y = 1x - 6....or just y = x - 6 <===
Answer:
The value of Car B will become greater than the value of car A during the fifth year.
Step-by-step explanation:
Note: See the attached excel file for calculation of beginning and ending values of Cars A and B.
In the attached excel file, the following are used:
Annual Depreciation expense of Car A = Initial value of Car A * Depreciates rate of Car A = 30,000 * 20% = 6,000
Annual Depreciation expense of Car B from Year 1 to Year 6 = Initial value of Car B * Depreciates rate of Car B = 20,000 * 15% = 3,000
Annual Depreciation expense of Car B in Year 7 = Beginning value of Car B in Year 7 = 2,000
Conclusion
Since the 8,000 Beginning value of Car B in Year 5 is greater than the 6,000 Beginning value of Car A in Year 5, it therefore implies that the value Car B becomes greater than the value of car A during the fifth year.
