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Gnom [1K]
3 years ago
12

Expanded form and word form for 3.4

Mathematics
2 answers:
Neko [114]3 years ago
7 0
3+.4

Three and four tenths
Leni [432]3 years ago
7 0
The answer is 

3.0 + 0.4
You might be interested in
A: l = h - 7.0<br> B: l= 9/16h<br> C:h = 9/16L<br> D:h = L - 7.0
Georgia [21]

Answer:

A

Step-by-step explanation: The answer is A

3 0
3 years ago
3t+10=16 what is the answer
nevsk [136]
3t+10=16
    -10  -10
3T=6
T=2

6 0
3 years ago
Read 2 more answers
Please help, seriously confused
Rufina [12.5K]
Original height = original width = x mm

1. She made an enlarged copy...
height = 2x
width = 2x

2. She cut off a rectangle...
height = 2x
width = \frac{2}{3} *2x= \frac{4}{3}x

3.She doubled the width...
height = 2x
width = 2*\frac{4}{3}x = \frac{8}{3}x

height * width = area

2x * \frac{8}{3}x=139 \ 968  \\ \\ \frac{16}{3}x^2= 139 \ 968 \\\\ x^2=139 \ 968: \frac{16}{3}=139 \ 968 * \frac{3}{16}=  8 \ 748*3 = 26 \ 244 \\  \\ x= \sqrt{26 \ 244} = 162 \ mm

Original height was 162 mm 
6 0
3 years ago
How do you find DE, Round to nearest 10th
Sergeu [11.5K]

Answer:  DE\approx6.0

Step-by-step explanation:

Observe in the figure given in the exercise that four right triangles are formed.

In this case you can use the following Trigonometric Identity to solve this exercise:

cos\alpha=\frac{adjacent}{hypotenuse}

From the figure you can identify that:

\alpha =53\°\\\\hypotenuse=10\\\\adjacent=BE=DE

Then, you can substitute values:

cos(53\°)=\frac{DE}{10}

The next step is to solve for DE in order to find its value. This is:

10*cos(53\°)=DE\\\\DE=6.01

Finally, rounding the result to the nearest tenth, you get that this is:

DE\approx6.0

7 0
3 years ago
What's the next ones?
hammer [34]
3.) 2 × 0.5 = 1 4.) -2 × -0.5 = 1
4 0
3 years ago
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