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Slav-nsk [51]
4 years ago
6

Factor out the greatest common factor from 6y2+27y using the Distributive Property.

Mathematics
1 answer:
Novay_Z [31]4 years ago
7 0

Answer:

3y(2y + 9)

Step-by-step explanation:

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blsea [12.9K]
Add 20 to 24 and divide everything by 4
3 0
3 years ago
Read 2 more answers
Ky wants to buy three shirts, which were originally priced 49.96 each. The store will discount the price of the third shirt by 5
FromTheMoon [43]

49.96 + 49.96 + (49.96x.5)

99.92+24.94=124.86 divide 7.1 and 124.86 which gives you 17.58591549295775 but I’m guessing u round so 17.59 and add that to 124.86which equals 142.45. The total cost is 142.45. But each shirt is 49.96 and the third is 24.94. Don’t forget the dollar sign and have a good day! :)

3 0
4 years ago
Solve the inequality: h−5≥−16h-5≥-16
erastova [34]
We need to rearrange this to solve.
h-5 ≥ -16h-5 ≥ -16
Subtract -5 from all of it we get:
h ≥ -16h ≥ -11

Therefore none of the answers are correct.
8 0
4 years ago
Which choices are equivalent to the expression below? Check all that apply.<br> 5 square root 3
blsea [12.9K]

Option A: \sqrt{75}

Option C: \sqrt{15} \cdot \sqrt{5}

Option F: \sqrt{25} \cdot \sqrt{3}

Solution:

Given expression is 5 \sqrt{3}.

Option A: \sqrt{75}

\sqrt{75}=\sqrt{25\times3}

       =\sqrt{5^2\times3}

       =5\sqrt{3}

Hence \sqrt{75} is equivalent expression of 5 \sqrt{3}.

Option B: \sqrt{45}

\sqrt{45}=\sqrt{9\times5}

       =\sqrt{3^2\times5}

       =3\sqrt{5}

Hence \sqrt{45} is not equivalent expression of 5 \sqrt{3}.

Option C: \sqrt{15} \cdot \sqrt{5}

\sqrt{15} \cdot \sqrt{5}=\sqrt{15\times5}

              =\sqrt{75}

              =5\sqrt{3}    (proved in option A)

Hence \sqrt{15} \cdot \sqrt{5} is equivalent expression of 5 \sqrt{3}.

Option D: \sqrt{3} \cdot \sqrt{5}

\sqrt{3} \cdot \sqrt{5}=\sqrt{3\times5}

            =\sqrt{15}

Hence \sqrt{3} \cdot \sqrt{5} is not equivalent expression of 5 \sqrt{3}.

Option E: 75

75 is a whole number.

Hence 75 is not equivalent expression of 5 \sqrt{3}.

Option F: \sqrt{25} \cdot \sqrt{3}

\sqrt{25} \cdot \sqrt{3}=\sqrt{25\times3}

              =\sqrt{75}

              =5\sqrt{3}    (proved in option A)

Hence \sqrt{25} \cdot \sqrt{3} is equivalent expression of 5 \sqrt{3}.

Therefore, \sqrt{75},\ \  \sqrt{15} \cdot \sqrt{5}, \  \ \sqrt{25} \cdot \sqrt{3} are all equivalent expressions of 5 \sqrt{3}.

6 0
3 years ago
Miyoko's goal is to earn more than this week. She earns for every day she works as a cryptographer, and
Kaylis [27]

Answer:

$250*C + $180*G = $950

Step-by-step explanation:

Solving for G, it is G = (950 - 250C)/180

Solving for C, it is C = (950 - 180G)/250

6 0
3 years ago
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