Answer:
An official playing field (including end zones) for the Indoor Football League has a length 29 yd longer than its width. The perimeter of the rectangular field is 158 yd. Find the length and width of the field
Step-by-step explanation:
V_cone = 1/3 pi * r^2 * h
V_cylinder = pi*r^2*h
If you multiply the cone's volume by 3 then you get the cylinder's volume. They become the same formula
3 V_cone = pi r^2 h
Since the cone's volume is 36pi They cylinder's volume is 3*36pi = 108 pi
Answer:
x = -45, y = -40
Step-by-step explanation:
Based on the first clue, we find out that
x + 5 = y
5x = 6y + 15
We can re-write the first equation to x = y - 5.
Therefore, the second equation can also be written as 5(y - 5) = 6y + 15
This can be simplified to 5y - 25 = 6y + 15
We can subtract 6y from each side, and add 25 to each side;
5y - 6y = 15 + 25
Therefore, -y = 40
Therefore y = -40.
Now let's plug this back into the original equation, to get : x + 5 = -40
x=-45
1 )
1st and 2nd equation (multiply 1st by -2 ):
-2x - 10 y + 8 z = 20
2 x - y + 5 z = -9
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- 11 y + 13 z = 11 / * ( -20 )
1st and 3rd:
- 2 x - 10 y + 8 z = 20
2 x - 10 y - 5 z = 0
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- 20 x + 3 z = 20 / * 11
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220 y - 260 z = -220
- 220 y + 33 z = 220
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z = 0, y = -1, x = - 5
2 )
2 x - y + 5 = -4
- 2 x + 3 y - 5 = - 10
Substitution: y = 2 x + 9
- 2 x + 3(2 x + 9 ) = -5
4 x = - 32, x = -8, y = -7, z = 5
3 )
x + y + z = 11
1.5 x+3 y +1.5 z = 21
x = 2 y
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3 y + z = 11 / * (-2)
6 y + 1.5 z = 21
------------------------
- 6 y - 2 z = -22
6 y + 1.5 z = 21
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-0.5 z = -1, z = 2, y = 3, z = 6
Answer: the store used 6 pounds of peanuts, 3 pounds of almonds and 2 pounds of raisins.
Answer:
ara ara
Step-by-step explanation:
