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Solnce55 [7]
3 years ago
6

A roller coaster, traveling with an initial speed of 15 meters per second, decelerates uniformly at –7.0 m/s2 to a full stop. Ap

proximately how far does the roller coaster travel during its deceleration?
Physics
1 answer:
liubo4ka [24]3 years ago
4 0

Answer:

 Roller coaster will travel 16.07 meter before coming to stop.

Explanation:

We have equation of motion, v^2=u^2+2as, where u is the initial velocity, u is the final velocity, s is the displacement and a is the acceleration.

In this case we have final velocity = 0 m/s, initial velocity = 15 m/s, and acceleration = -7 m/s^2.

0^2=15^2-2*7*s\\ \\ 14s=225\\ \\ s=16.07m

So, roller coaster will travel 16.07 meter before coming to stop.

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The law of conservation of angular momentum expresses that when no outer torque follows up on an article, no difference in precise force will happen.

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If there is an unbalanced force acting on an object, the object will?
Nonamiya [84]

Answer:

A

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2 years ago
How does the density of most metals compare to most non metals?
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2 years ago
A body has masses of 0.013kg and 0.012kg in oil and water respectively, if the relative density of oil is 0.875, calculate the m
konstantin123 [22]

Answer:

the mass of the body is 0.02 kg.

Explanation:

Given;

relative density of the oil, \gamma _0 = 0.875

mass of the object in oil, M_o = 0.013 kg

mass of the object in water, M_w = 0.012 kg

let the mass of the object in air = M_a

weight of the oil, W_0 = M_a - 0.013

weight of the water, W_w = M_a - 0.012

The relative density of the oil is given as;

\gamma_0 = \frac{density \ of \ oil }{density \ of \ water} = \frac{W_0}{W_w} = \frac{M_a -0.013}{M_a -0.012} \\\\0.875 = \frac{M_a -0.013}{M_a -0.012}\\\\0.875(M_a - 0.012) = M_a - 0.013\\\\0.875M_a - 0.0105 = M_a -0.013\\\\0.875M_a - M_a = 0.0105 - 0.013\\\\-0.125 M_a = -0.0025\\\\M_a = \frac{0.0025}{0.125} \\\\M_a = 0.02 \ kg

Therefore, the mass of the body is 0.02 kg.

6 0
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