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Mice21 [21]
3 years ago
6

n astronaut has left the International Space Station to test a new space scooter. Her partner measures the following velocity ch

anges, each taking place in a time interval 11.2 s . What are the average acceleration in each interval? Assume that the positive direction is to the right.
Physics
1 answer:
Ira Lisetskai [31]3 years ago
3 0

Answer:-

-1 m/s^2

Explanation:

The average acceleration is given by dividing the change in velocity by change in time;

a_f=\frac{v_f-v_i}{t_f-t_i}

=\frac{(0-11.2)}{(11.2-0)}=-1 m/s^2

the point to be noted here is if the velocity is to the left we substitute it with a negative sign and if it is to the right we substitute it with a positive sign.

You might be interested in
In Hooke’s law, what does the x represent?
Mice21 [21]

Answer:   C

X = Displacement of the spring

Hooke's law: It states that the applied force F is proportional to the  displacement of spring .

            F ∝ x

            Where, x = displacement of spring in meters

                         F = force, measured in Newtons

In another words The force F is equal to the constant K times the disparagement.

            F = k.x

            Where k is constant and it depends on elastic material.

            Spring has restorative force.  

If the spring moves in opposite direction then,

           F = - k.x

A negative sign indicates that the spring resists and force is to the left. The compression of the spring is greater than the restoring force.  

   Example: A mass 'm' stretches a spring at a displacement x.    

6 0
4 years ago
Two charged objects have a repulsive force of 0.050 N. If the charge of both of the objects is doubled, then what is the new for
grandymaker [24]

Answer: 4 times grease

Explanation: Force F= C · q1·q2/r². C = Coulomb's constant.

If charges double you have 2q1 and 2q2.

7 0
3 years ago
Provide an example of when momentum is conserved and explain your answer you can get 10 PTS if answered with a good explaination
dezoksy [38]

Answer:

m_1=8\ kg,\ m_2=6\ kg,\ v_1=12\ m/s, v_2=4\ m/s,\ v_1'=-6\ m/s,\ v_2'=28\ m/s

Explanation:

<u>Conservation of Momentum </u>

The total momentum of a system of two particles is

p=m_1v_1+m_2v_2

Where m1,m2,v1, and v2 are the respective masses and velocities of the particles at a given time. Then, the two particles collide and change their velocities to v1' and v2'. The final momentum is now

p'=m_1v_1'+m_2v_2'

The momentum is conserved if no external forces are acting on the system, thus

m_1v_1+m_2v_2=m_1v_1'+m_2v_2'

Let's put some numbers in the problem and say

m_1=8\ kg,\ m_2=6\ kg,\ v_1=12\ m/s, v_2=4\ m/s,\ v_1'=-6\ m/s,\ v_2'=28\ m/s

(8)(12)+(6)(4)=(8)(-6)+(6)(28)

96+24=-48+168

120=120

It means that when the particles collide, the first mass returns at 6 m/s and the second continues in the same direction at 28 m/s

4 0
3 years ago
An astronaut sitting on the launch pad on Earth's surface is 6,400 kilometers from Earth's center and weighs 400 newtons. Calcul
PIT_PIT [208]

Answer:

weight at height = 100 N .

Explanation:

The problem relates to variation of weight  due to change in height .

Let g₀ and g₁ be acceleration due to gravity , m is mass of the object .

At the surface :

Applying Newton's law of gravitation

mg₀ = G Mm / R²

At height h from centre

mg₁ = G Mm /h²

Given mg₀ = 400 N

400 = G Mm / R²

400 = G Mm / (6400 x 10³ )²

G Mm = 400 x (6400 x 10³ )²

At height h from centre

mg₁ =  400 x (6400 x 10³ )²/ ( 2 x 6400 x 10³)²

= 400 / 4

= 100 N .

weight at height = 100 N

5 0
3 years ago
How can a person detect infrared rays without an instrument?
natita [175]
So we want to know how can we detect infrared rays without an instrument. Infrared rays or heat, are a part of electromagnetic spectrum. We have specialized nerve cells in our skin called thermoreceptors that can detect differences in temperature that are produced by infrared part of EM spectrum.
7 0
3 years ago
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