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timurjin [86]
3 years ago
6

Change the fraction to a decimal with division 1/10

Mathematics
2 answers:
steposvetlana [31]3 years ago
8 0
0.1 will be the answer to your question
Viktor [21]3 years ago
7 0

Answer: 0.1

Step-by-step explanation: you only need to add zero to the first value,

for example if you have 1/10, you add zero, getting the next equation

10/10 if you add a zero to value you can add a zero to the result getting the following result

10/10=0. in this point both values are divisible

and 10 between 10 is equal to 1

as you finish add zeros you can add a point and after the 1 getting this result

1/10 = 0.1

 

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A company establishes a fund of 120 from which it wants to pay an amount,C, to any of its 20 employees who achieve a high-perfor
Leno4ka [110]

Answer:

C=120/2=60

Step by step Explanation'

To solve this problem, we will need to apply trial-and-error calculation with the binomial distribution, even though it appears like Central Limit Theorem but it's not.

For us to know the value of C , we will look for a minimum integer such that having 'n' number of high performance level of employee has the probability below 0.01.

Determine the maximum value of C, then the maximum value that C can have is 120/n

Let us represent X as the number of employees with high performance with a binomial distribution of

P =0.02( since the percentage of chance of achieving a high performance level is 2%)

n = 20 ( number of employees who achieve a high performance level)

The probability of X= 0 can be calculated

P( X= 0) = 0.98^n

P(X=0)=0.98^20

P(X=0)=0.668

P(X=1)=0.02*20*0.98^19

P(X=1)=0.272

P(X=2)=0.02^2*20*0.98^18

P(X=2)=0.053

Summation of P( X= 0)+ P( X= 1)+P( X= 2) will give us the value of 0.993 which is greater than 0.99( 1% that the fund will be inadequate to cover all payments for high performance.)

BUT the summation of P( X= 0)+ P( X= 1) will give the value of 0.94 which doesn't exceed the 0.99 value,

Therefore, the minimum value of integer in such a way that P(X >2) is less than 0.01 have n= 2

then the maximum value that C can have is 120/n

C=120/2=60

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