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Nady [450]
3 years ago
14

The length of the shadow of a building is 150 meters, as shown below: The shadow of a building is 150 meters long. The acute ang

le that the shadow makes with the line joining the top of the building to the end of the shadow measures 45 degrees. What is the height of the building?
Mathematics
2 answers:
Pavel [41]3 years ago
5 0

in a triangle with 2 45 degree angles and a 90 degree angle, the opposite and the adjacent sides are always equal, making the answer 150m

mafiozo [28]3 years ago
3 0
So first you want to draw out you triangle and label everything so side a would be x, side b would be 15 and c would be x
next the angles need to be label 
and finally the anwser is 150m

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Answer:

The volume is decreasing at the rate of 1.396 cubic inches per minute

Step-by-step explanation:

Given

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\frac{dr}{dt} =\frac{1}{2} --- rate of the radius

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r = 2

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Required

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The volume of a cone is:

V = \frac{\pi}{3}r^2h

Differentiate with respect to time (t)

\frac{dV}{dt} = \frac{\pi}{3}(2rh \frac{dr}{dt} + r^2 \frac{dh}{dt})

Substitute values for the known variables

\frac{dV}{dt} = \frac{\pi}{3}(2*2*\frac{1}{3}* \frac{1}{2} - 2^2 *\frac{1}{3})

\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}* \frac{1}{2} - \frac{4}{3})

\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}(\frac{1}{2} - 1))

\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}*- 1)

\frac{dV}{dt} = -\frac{\pi}{3}*\frac{4}{3}

\frac{dV}{dt} = -\frac{22}{7*3}*\frac{4}{3}

\frac{dV}{dt} = -\frac{22}{21}*\frac{4}{3}

\frac{dV}{dt} = -\frac{88}{63}

\frac{dV}{dt} =-1.396in^3/min

The volume is decreasing at the rate of 1.396 cubic inches per minute

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