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Alona [7]
3 years ago
13

Find the midpoint of the segment with the given endpoints.

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
8 0
Hey. :)

<span>Find the midpoint of the segment with the given endpoints. 
D(5, 1) and E(13, 11)

(9, 6)</span>
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Accidents on highways are one of the main causes of death or injury in developing countries and the weather conditions have an i
pashok25 [27]

Answer:

0.105 = 10.5% probability that an accident results in a death.

Step-by-step explanation:

What is the probability that an accident results in a death?

5% of 60%(sunny)

25% of 20%(foggy)

12.5% of 20%(rainy)

So

p = 0.05*0.6 + 0.25*0.2 + 0.125*0.2 = 0.105

0.105 = 10.5% probability that an accident results in a death.

6 0
3 years ago
3,408 divided by 41 <br><br> Explanation in traditional method<br><br><br><br> 52 POINTS PLS HELP
Furkat [3]

Answer:

83.1219512195

Step-by-step explanation:

Hope this helps!

7 0
2 years ago
Read 2 more answers
A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int
Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}

By expanding the previous equation:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0

Since there is no accumulation within the tank, expression is simplified to this:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}, where c(0) = 0 \frac{pounds}{gallon}.

\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}

The solution of this equation is:

c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})

The salt concentration after 8 minutes is:

c(8) = 0.166 \frac{pounds}{gallon}

The instantaneous amount of salt in the tank is:

m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds

3 0
3 years ago
Malcolm bought 6 bowls for $13.20. whats the unit rate<br><br><br> need the work
Whitepunk [10]
Hello!

You have to find the cost of one bowl

To find this you take the cost of all the bowls and divide it by the amount of bowls

13.20 / 6 = 2.2

The answer is $2.20

Hope this helps!
8 0
3 years ago
Read 2 more answers
One of your friends gives you $10 for a charity walkathon. Another friend gives you an amount per mile. After 5 miles, you have
irinina [24]
One of your friends gives you $10 for a charity walkathon -- this is your beginning amount.
Another friend gives you an amount per mile -- you will to calculate this value.
After 5 miles, you have raised $13.50 total --
-- Since one friend gave you $10.00, subtract this from the $13.50 to give you the amount by walking the 5 miles 
-- $10.00 - $13.50 = $3.50
-- Since you walked 5 miles, divide $3.50 by 5 to give you $0.70 per mile earned.

So, an equation that represents the amount of money earned is: y = $0.70x+$10.00.
This is in slope-intercept form; the slope is $0.70 and represents the amount of money earned per mile and the intercept is $10.00 and represents the initial amount of money that you were given.
7 0
4 years ago
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