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Alona [7]
3 years ago
13

Find the midpoint of the segment with the given endpoints.

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
8 0
Hey. :)

<span>Find the midpoint of the segment with the given endpoints. 
D(5, 1) and E(13, 11)

(9, 6)</span>
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I met this hella weird cryptic dude who interviewed me and gave me this puzzle. Solve it within 12 hours and ill let you know wh
Elena-2011 [213]

no cheating thanks <3

6 0
3 years ago
What is 2700 divided 90​
crimeas [40]

Answer:

30

Step-by-step explanation:

2700/90 = 30

27/9 = 3

100/10 = 10

3*10 = 30

8 0
3 years ago
There is a bag filled with 5 blue and 6 red marbles.
Sidana [21]

Answer:

6/11

Step-by-step explanation:

probability

6+5=11

so 6/11

6 0
3 years ago
Read 2 more answers
A rectangular magazine cover is photocopied by using a scale factor of One-third. The length of the photocopy of the magazine co
seraphim [82]

Answer: "reduced by a factor of One-third."

Step-by-step explanation:

Suppose that the original magazine has a length L and a width W.

If it is photocopied using a scale factor of K, then the measures of the photocopy will be:

length = K*L

Width = K*W

In this case, the scale factor is K = 1/3, then the measures of the photocopy will be:

length = (1/3)*L = L/3

Width = (1/3)*W = W/3

For usual notation:

When k > 1, we have an enlargement by a factor k

when 0 < k < 1, we have a reduction by a factor k

in this case, k = 1/3, then:

We have a reduction by a factor of 1/3

The correct option is:

"reduced by a factor of One-third."

7 0
3 years ago
Read 2 more answers
8. The Last Supper
Salsk061 [2.6K]

The number of possible seats is an illustration of permutation

There are 1728 possible sitting arrangements

<h3>How to determine the number of seats</h3>

From the question, we have the following highlights:

  • Chris can only take 1 seat (i.e. the central seat)
  • Jo can take 2 seats (i.e. the seats adjacent the central seat)
  • Alex, Barb and Dave can take 3! number of seats
  • Eddie, Fred, and Gareth can take 3! number of seats on the right of Chris.
  • The remaining 4 adults do not have preference, then they can seat in 4! ways

So, the number of sitting arrangement is:

n = 1 * 2 * 3! * 3! * 4!

Evaluate the product

n = 1728

Hence, there are 1728 possible sitting arrangements

Read more about permutation at:

brainly.com/question/12468032

7 0
2 years ago
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